anonymous
  • anonymous
help! graphing piece wise function
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
@peachpi
anonymous
  • anonymous
|dw:1439342436794:dw|
anonymous
  • anonymous
this is the graph I'm working on

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anonymous
  • anonymous
@Hero @nincompoop @pooja195
anonymous
  • anonymous
what's the function?
anonymous
  • anonymous
It doesn't give the whole function to me
anonymous
  • anonymous
|dw:1439342819554:dw|
anonymous
  • anonymous
this is what I have, the functions are missing, the graph I drew above is supposed to be interpreted so the function can be filled in
anonymous
  • anonymous
oh ok. are you sure the bottom one is -3≤x≤3? It looks like it should be 3 ≤ x ≤ maybe 4 or 5
anonymous
  • anonymous
and is it a curve or a straight line for |dw:1439343210666:dw|
anonymous
  • anonymous
straight
anonymous
  • anonymous
yes I'm sure the numbers are correct, The point is just big
anonymous
  • anonymous
can you take a picture of the problem or give me coordinates for the points? |dw:1439343890005:dw|
anonymous
  • anonymous
once you have the two end points for the bottom segment, we can write an equation in y = mx + b form, but we need the exact points to get it right
anonymous
  • anonymous
That's the graph they gave me in the lesson, it's not precise
anonymous
  • anonymous
the points are -1,1 and 3,5
anonymous
  • anonymous
-1,1 is a straight line
anonymous
  • anonymous
3, 5 is a sloped line
anonymous
  • anonymous
that runs between 3,2 and 5,4
anonymous
  • anonymous
the equation they give me is |dw:1439344737330:dw|
tkhunny
  • tkhunny
The regions CANNOT overlap if it is the definition of a FUNCTION.
Loser66
  • Loser66
|dw:1439344850372:dw|
anonymous
  • anonymous
yes @Loser66
Loser66
  • Loser66
ok, for the first piece, f(x) = 3 when \(-1\leq x\leq 1\), got this part? |dw:1439345082272:dw|
anonymous
  • anonymous
yes
Loser66
  • Loser66
for the second piece, it is a slant line. Can you find the equation of that line by finding the slope??
Loser66
  • Loser66
|dw:1439345172848:dw|
anonymous
  • anonymous
the slope is 1
anonymous
  • anonymous
or 2/2
Loser66
  • Loser66
yup, now, pick one point
anonymous
  • anonymous
1,1
Loser66
  • Loser66
nope, the point ON the line. (given points)
Loser66
  • Loser66
|dw:1439345247505:dw|
Loser66
  • Loser66
which one??
Loser66
  • Loser66
just pick, either of them.
anonymous
  • anonymous
0,3
Loser66
  • Loser66
(0,3) is NOT on the given line.
Loser66
  • Loser66
YOu have only 2 given points (3,2) and (5,4). Pick one of them. YOu CANNOT pick other point
anonymous
  • anonymous
3,2
Loser66
  • Loser66
ok, the line is y = mx +b where m is the slope. And we know that m =1 hence y = x +b -x both sides, what do you get?
Loser66
  • Loser66
|dw:1439345490498:dw|
Loser66
  • Loser66
My method is too difficult to understand??
tkhunny
  • tkhunny
Just graph the two pieces as if no restriction existed. Later, go cross out the stuff where the Domain is not specified.
Loser66
  • Loser66
@tkhunny they didn't give the function. We have to find it. That is the problem \(f(x) =\begin{cases}--------if~~-1\leq x\leq1\\---------if~~~3\leq x\leq 5\end{cases}\)
tkhunny
  • tkhunny
I see. We're given the graph? @Kaelyn78 , you should know the two-point form of a line - or its cleaner variant, the point-slope form. Heard of them?
tkhunny
  • tkhunny
Please stop saying "function" when the Domains overlap.
anonymous
  • anonymous
I've heard of point slope form
tkhunny
  • tkhunny
Given the two points, calculate the slope. Use one of the points and the slope and fill in the values from the point-slope form. You will be done in no time.
Jack1
  • Jack1
u say that about calculating 2nd order derivatives of complex equations tho @tkhunny u crazy mathlete u ;)

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