help! graphing piece wise function

- anonymous

help! graphing piece wise function

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- anonymous

@peachpi

- anonymous

|dw:1439342436794:dw|

- anonymous

this is the graph I'm working on

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## More answers

- anonymous

@Hero @nincompoop @pooja195

- anonymous

what's the function?

- anonymous

It doesn't give the whole function to me

- anonymous

|dw:1439342819554:dw|

- anonymous

this is what I have, the functions are missing, the graph I drew above is supposed to be interpreted so the function can be filled in

- anonymous

oh ok. are you sure the bottom one is -3â‰¤xâ‰¤3?
It looks like it should be 3 â‰¤ x â‰¤ maybe 4 or 5

- anonymous

and is it a curve or a straight line for |dw:1439343210666:dw|

- anonymous

straight

- anonymous

yes I'm sure the numbers are correct, The point is just big

- anonymous

can you take a picture of the problem or give me coordinates for the points? |dw:1439343890005:dw|

- anonymous

once you have the two end points for the bottom segment, we can write an equation in y = mx + b form, but we need the exact points to get it right

- anonymous

That's the graph they gave me in the lesson, it's not precise

- anonymous

the points are -1,1 and 3,5

- anonymous

-1,1 is a straight line

- anonymous

3, 5 is a sloped line

- anonymous

that runs between 3,2 and 5,4

- anonymous

the equation they give me is |dw:1439344737330:dw|

- tkhunny

The regions CANNOT overlap if it is the definition of a FUNCTION.

- Loser66

|dw:1439344850372:dw|

- anonymous

yes @Loser66

- Loser66

ok, for the first piece, f(x) = 3 when \(-1\leq x\leq 1\), got this part? |dw:1439345082272:dw|

- anonymous

yes

- Loser66

for the second piece, it is a slant line. Can you find the equation of that line by finding the slope??

- Loser66

|dw:1439345172848:dw|

- anonymous

the slope is 1

- anonymous

or 2/2

- Loser66

yup, now, pick one point

- anonymous

1,1

- Loser66

nope, the point ON the line. (given points)

- Loser66

|dw:1439345247505:dw|

- Loser66

which one??

- Loser66

just pick, either of them.

- anonymous

0,3

- Loser66

(0,3) is NOT on the given line.

- Loser66

YOu have only 2 given points (3,2) and (5,4). Pick one of them. YOu CANNOT pick other point

- anonymous

3,2

- Loser66

ok, the line is y = mx +b where m is the slope. And we know that m =1
hence y = x +b
-x both sides, what do you get?

- Loser66

|dw:1439345490498:dw|

- Loser66

My method is too difficult to understand??

- tkhunny

Just graph the two pieces as if no restriction existed. Later, go cross out the stuff where the Domain is not specified.

- Loser66

@tkhunny they didn't give the function. We have to find it. That is the problem
\(f(x) =\begin{cases}--------if~~-1\leq x\leq1\\---------if~~~3\leq x\leq 5\end{cases}\)

- tkhunny

I see. We're given the graph? @Kaelyn78 , you should know the two-point form of a line - or its cleaner variant, the point-slope form. Heard of them?

- tkhunny

Please stop saying "function" when the Domains overlap.

- anonymous

I've heard of point slope form

- tkhunny

Given the two points, calculate the slope.
Use one of the points and the slope and fill in the values from the point-slope form.
You will be done in no time.

- Jack1

u say that about calculating 2nd order derivatives of complex equations tho @tkhunny u crazy mathlete u ;)

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