help! graphing piece wise function

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help! graphing piece wise function

Mathematics
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|dw:1439342436794:dw|
this is the graph I'm working on

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Other answers:

what's the function?
It doesn't give the whole function to me
|dw:1439342819554:dw|
this is what I have, the functions are missing, the graph I drew above is supposed to be interpreted so the function can be filled in
oh ok. are you sure the bottom one is -3≤x≤3? It looks like it should be 3 ≤ x ≤ maybe 4 or 5
and is it a curve or a straight line for |dw:1439343210666:dw|
straight
yes I'm sure the numbers are correct, The point is just big
can you take a picture of the problem or give me coordinates for the points? |dw:1439343890005:dw|
once you have the two end points for the bottom segment, we can write an equation in y = mx + b form, but we need the exact points to get it right
That's the graph they gave me in the lesson, it's not precise
the points are -1,1 and 3,5
-1,1 is a straight line
3, 5 is a sloped line
that runs between 3,2 and 5,4
the equation they give me is |dw:1439344737330:dw|
The regions CANNOT overlap if it is the definition of a FUNCTION.
|dw:1439344850372:dw|
ok, for the first piece, f(x) = 3 when \(-1\leq x\leq 1\), got this part? |dw:1439345082272:dw|
yes
for the second piece, it is a slant line. Can you find the equation of that line by finding the slope??
|dw:1439345172848:dw|
the slope is 1
or 2/2
yup, now, pick one point
1,1
nope, the point ON the line. (given points)
|dw:1439345247505:dw|
which one??
just pick, either of them.
0,3
(0,3) is NOT on the given line.
YOu have only 2 given points (3,2) and (5,4). Pick one of them. YOu CANNOT pick other point
3,2
ok, the line is y = mx +b where m is the slope. And we know that m =1 hence y = x +b -x both sides, what do you get?
|dw:1439345490498:dw|
My method is too difficult to understand??
Just graph the two pieces as if no restriction existed. Later, go cross out the stuff where the Domain is not specified.
@tkhunny they didn't give the function. We have to find it. That is the problem \(f(x) =\begin{cases}--------if~~-1\leq x\leq1\\---------if~~~3\leq x\leq 5\end{cases}\)
I see. We're given the graph? @Kaelyn78 , you should know the two-point form of a line - or its cleaner variant, the point-slope form. Heard of them?
Please stop saying "function" when the Domains overlap.
I've heard of point slope form
Given the two points, calculate the slope. Use one of the points and the slope and fill in the values from the point-slope form. You will be done in no time.
u say that about calculating 2nd order derivatives of complex equations tho @tkhunny u crazy mathlete u ;)

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