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sorry it went away

oh ok

before we begin is it clear that two factors are \((x-5)\) and \((x+3)\)?

yes

you want the easy way, or the real real easy way?

real real easy

ok actually lets to the easy way first then the real real easy way

add 4 to both sides and get
\[x^2+2x+5=0\] and that is your polynomial

those arent any options tho :(

your final job is to multiply \[(x-5)(x+3)(x^2+2x+5)\]

if it was me, i would cheat so as not to screw up the algebra when multiplying

you know how to do that?

wait let me try again

ok i will leave you to it, then show you how to get the answer for sure

yeah the answer i get does not match up with my choices

http://www.wolframalpha.com/input/?i=%28x-5%29%28x%2B3%29%28x^2%2B2x%2B5%29

see if that one does

Oh thank-you! maybe i was multiplying something wrong!

that is why i said "cheat" is is easy to make a mistake when multiplying all this muck out

yw