purplemexican
  • purplemexican
help please
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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purplemexican
  • purplemexican
tkhunny
  • tkhunny
Please provide the Right-Triangle definition of the Cosine.
purplemexican
  • purplemexican
everywhere

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purplemexican
  • purplemexican
the most i can tell you is what im looking for
tkhunny
  • tkhunny
You cannot have been given this problem without the basic Right-Triangle definitions of Sine, Cosine, and Tangent. What are they?
purplemexican
  • purplemexican
do i know what?
purplemexican
  • purplemexican
i have been given what you see
purplemexican
  • purplemexican
and 4 answer choices
purplemexican
  • purplemexican
if i knew earlier today i dont remember now
tkhunny
  • tkhunny
Hogwash, unless this is a placement test. If this is a placement test, you should get this problem wrong so that you are placed in the correct course this semester.
purplemexican
  • purplemexican
well i dont want you to do it for me i would like a step by step tho
purplemexican
  • purplemexican
im in summerschool
purplemexican
  • purplemexican
ive been doing algebra 2 since 9 am to 4:30 for the past few days im half out of my wits with this stuff now
tkhunny
  • tkhunny
So? Then take a break. Eat something. Get some sleep. Read this: https://www.bing.com/images/search?q=right+triangle+definition+of+sine&view=detailv2&&id=215DE835C6C9753A48093FB88A6FD84396447F91&selectedIndex=0&ccid=6mvOJUX%2f&simid=608044099930951339&thid=JN.N04zAIXgt9vGSoV1a0kegw&ajaxhist=0
purplemexican
  • purplemexican
i have till 4:30 tomorrow to finish about 50 questions i would love to take a brake i really wold
tkhunny
  • tkhunny
Did you read it?
purplemexican
  • purplemexican
yes it make sence
tkhunny
  • tkhunny
Okay, now solve. What does it want and how shall you find it?
purplemexican
  • purplemexican
i have one minuet im gonna guess on the quiz then come back and figure it out
purplemexican
  • purplemexican
didnt even get to guess so im looking for angle FHE right and or cos(theta) right?
tkhunny
  • tkhunny
\(\cos(\angle FHE) = \dfrac{Adjacent}{Hypotenuse}\) You know neither the Adjacent Side (FH) nor the Hypotenuse (EH). How shall we find them?
purplemexican
  • purplemexican
i have 2 angles and a side i could find the other sides of the one triangle and then i would have one of the sides
tkhunny
  • tkhunny
Good. How about \(\triangle{HGF}\)? Can that help us find FH?
purplemexican
  • purplemexican
yes it would
tkhunny
  • tkhunny
It's a 45-45-90 Right Triangle. What is the relationship between the Leg and the Hypotenuse?
purplemexican
  • purplemexican
leg FH is 4 right
tkhunny
  • tkhunny
How did you get that? One for free: \(\sqrt{8}\cdot\sqrt{2} = \sqrt{16} = 4\) I believe you have it! Now, we know the "Adjacent". Now, off to your Pythagorean Theorem to find the Hypotenuse, EH.
purplemexican
  • purplemexican
a^2+b^2=c^2\[4^2+3^2=5^2 \] and or 16+9=25 \[c=\sqrt{25}\] or c=5
purplemexican
  • purplemexican
@tkhunny do you concur?
tkhunny
  • tkhunny
We have the hypotenuse. Now, you can solve the problem. What is the requested cosine?
purplemexican
  • purplemexican
indeed
tkhunny
  • tkhunny
Eventually, you should also recognize "Pythagorean Triples" - at least 3-4-5 and 5-12-13. There are many others.
purplemexican
  • purplemexican
i get cos(37)=0.765
tkhunny
  • tkhunny
No one cares about those decimals or degrees. \(\cos\left(\angle{FHE}\right) = \dfrac{4}{5}\) - Done!
purplemexican
  • purplemexican
thank you so much i appreciate the help
tkhunny
  • tkhunny
You got it. Keep up the good work. Start earlier so you CAN take a break. :-)

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