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purplemexican
 one year ago
help please
purplemexican
 one year ago
help please

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tkhunny
 one year ago
Best ResponseYou've already chosen the best response.1Please provide the RightTriangle definition of the Cosine.

Purplemexican
 one year ago
Best ResponseYou've already chosen the best response.1the most i can tell you is what im looking for

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.1You cannot have been given this problem without the basic RightTriangle definitions of Sine, Cosine, and Tangent. What are they?

Purplemexican
 one year ago
Best ResponseYou've already chosen the best response.1i have been given what you see

Purplemexican
 one year ago
Best ResponseYou've already chosen the best response.1and 4 answer choices

Purplemexican
 one year ago
Best ResponseYou've already chosen the best response.1if i knew earlier today i dont remember now

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.1Hogwash, unless this is a placement test. If this is a placement test, you should get this problem wrong so that you are placed in the correct course this semester.

Purplemexican
 one year ago
Best ResponseYou've already chosen the best response.1well i dont want you to do it for me i would like a step by step tho

Purplemexican
 one year ago
Best ResponseYou've already chosen the best response.1im in summerschool

Purplemexican
 one year ago
Best ResponseYou've already chosen the best response.1ive been doing algebra 2 since 9 am to 4:30 for the past few days im half out of my wits with this stuff now

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.1So? Then take a break. Eat something. Get some sleep. Read this: https://www.bing.com/images/search?q=right+triangle+definition+of+sine&view=detailv2&&id=215DE835C6C9753A48093FB88A6FD84396447F91&selectedIndex=0&ccid=6mvOJUX%2f&simid=608044099930951339&thid=JN.N04zAIXgt9vGSoV1a0kegw&ajaxhist=0

Purplemexican
 one year ago
Best ResponseYou've already chosen the best response.1i have till 4:30 tomorrow to finish about 50 questions i would love to take a brake i really wold

Purplemexican
 one year ago
Best ResponseYou've already chosen the best response.1yes it make sence

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.1Okay, now solve. What does it want and how shall you find it?

Purplemexican
 one year ago
Best ResponseYou've already chosen the best response.1i have one minuet im gonna guess on the quiz then come back and figure it out

Purplemexican
 one year ago
Best ResponseYou've already chosen the best response.1didnt even get to guess so im looking for angle FHE right and or cos(theta) right?

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.1\(\cos(\angle FHE) = \dfrac{Adjacent}{Hypotenuse}\) You know neither the Adjacent Side (FH) nor the Hypotenuse (EH). How shall we find them?

Purplemexican
 one year ago
Best ResponseYou've already chosen the best response.1i have 2 angles and a side i could find the other sides of the one triangle and then i would have one of the sides

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.1Good. How about \(\triangle{HGF}\)? Can that help us find FH?

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.1It's a 454590 Right Triangle. What is the relationship between the Leg and the Hypotenuse?

Purplemexican
 one year ago
Best ResponseYou've already chosen the best response.1leg FH is 4 right

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.1How did you get that? One for free: \(\sqrt{8}\cdot\sqrt{2} = \sqrt{16} = 4\) I believe you have it! Now, we know the "Adjacent". Now, off to your Pythagorean Theorem to find the Hypotenuse, EH.

Purplemexican
 one year ago
Best ResponseYou've already chosen the best response.1a^2+b^2=c^2\[4^2+3^2=5^2 \] and or 16+9=25 \[c=\sqrt{25}\] or c=5

Purplemexican
 one year ago
Best ResponseYou've already chosen the best response.1@tkhunny do you concur?

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.1We have the hypotenuse. Now, you can solve the problem. What is the requested cosine?

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.1Eventually, you should also recognize "Pythagorean Triples"  at least 345 and 51213. There are many others.

Purplemexican
 one year ago
Best ResponseYou've already chosen the best response.1i get cos(37)=0.765

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.1No one cares about those decimals or degrees. \(\cos\left(\angle{FHE}\right) = \dfrac{4}{5}\)  Done!

Purplemexican
 one year ago
Best ResponseYou've already chosen the best response.1thank you so much i appreciate the help

tkhunny
 one year ago
Best ResponseYou've already chosen the best response.1You got it. Keep up the good work. Start earlier so you CAN take a break. :)
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