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anonymous
 one year ago
Using the given zero, find all other zeros of f(x).
2i is a zero of f(x) = x4  32x2  144
anonymous
 one year ago
Using the given zero, find all other zeros of f(x). 2i is a zero of f(x) = x4  32x2  144

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0if \(2i\) is a zero then so is \(2i\) therefore one factor is \(x+2i\) and another is \(x2i\) multiply the factors, get \[x^2+4\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0therefore this sucker factors as \[x^432x^2144=(x^2+4)(\text{something})\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02i, 12, 12 2i, 6i, 6i 2i, 6, 6 2i, 12i, 12i

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0on the other hand you can solve this directly without knowing any zeros, put \(u=x^2\) and solve \[u^232u144=0\] by factoring

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0those are my options

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0once you find \(u\) then replace it by \(x^2\) and solve

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you know how to factor this ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hint, one of the factors is \(x^2+4\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0probably want me to check?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0actually i change my mind probably not

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[x^431x144=0\\ (x^2+4)(x^2+bx+c)=0\]can factor easily how many times does \(4\) go in to \(144\)?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so this factors as \[(x^2+4)(x^236)=0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0final job it to solve \[x^236=0\] for \(x\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Oh i see what i did wrong now, thanks!
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