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anonymous

  • one year ago

Write the quadratic function in vertex form. y = x2 - 2x + 5

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  1. anonymous
    • one year ago
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    first coordinate of the vertex of \\(y=ax^2+bx+c\) is always \[-\frac{b}{2a}\]

  2. anonymous
    • one year ago
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    second coordinate of the vertex is what you get for \(y\) when you replace \(x\) by the first coordinate

  3. anonymous
    • one year ago
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    once you have the vertex \((h,k)\) then vertex form is \[y=a(x-h)^2+k\] in your case \(a=1,b=-2\)

  4. anonymous
    • one year ago
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    i can check your answer if you like

  5. anonymous
    • one year ago
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    y=(x+1)^2-4?

  6. anonymous
    • one year ago
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    oh no

  7. anonymous
    • one year ago
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    your signs are messed up

  8. anonymous
    • one year ago
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    \[-\frac{b}{2a}=-\frac{-2}{2\times (-1)}=1\]

  9. anonymous
    • one year ago
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    if you replace \(x\) by \(1\) you get \(4\) not \(-4\)

  10. anonymous
    • one year ago
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    so \[y=(x-1)^2+4\]

  11. anonymous
    • one year ago
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    Thanks!

  12. anonymous
    • one year ago
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    yw

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spraguer (Moderator)
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