anonymous
  • anonymous
Identify the 42nd term of an arithmetic sequence where a1 = −12 and a27 = 66.
Mathematics
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
\[a_{27}=-12+26\times d=66\] solve for \(d\) first
anonymous
  • anonymous
So, I got a27=14xd=66
anonymous
  • anonymous
no

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anonymous
  • anonymous
solve \[-12+26d=66\] first just like you solve any linear equation
anonymous
  • anonymous
d=3
anonymous
  • anonymous
add \(12\) to both sides, then divide both sides by \(26\) to solve for \(d\)
anonymous
  • anonymous
yeah \(d=3\)
anonymous
  • anonymous
Do we plug it back again?
anonymous
  • anonymous
so the 42 term is \[-12+41\times 3\]
anonymous
  • anonymous
111?
anonymous
  • anonymous
idk i didn't do it hold on
anonymous
  • anonymous
ok:)
anonymous
  • anonymous
yeah looks good

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