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anonymous

  • one year ago

Identify the 42nd term of an arithmetic sequence where a1 = −12 and a27 = 66.

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  1. anonymous
    • one year ago
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    \[a_{27}=-12+26\times d=66\] solve for \(d\) first

  2. anonymous
    • one year ago
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    So, I got a27=14xd=66

  3. anonymous
    • one year ago
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    no

  4. anonymous
    • one year ago
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    solve \[-12+26d=66\] first just like you solve any linear equation

  5. anonymous
    • one year ago
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    d=3

  6. anonymous
    • one year ago
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    add \(12\) to both sides, then divide both sides by \(26\) to solve for \(d\)

  7. anonymous
    • one year ago
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    yeah \(d=3\)

  8. anonymous
    • one year ago
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    Do we plug it back again?

  9. anonymous
    • one year ago
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    so the 42 term is \[-12+41\times 3\]

  10. anonymous
    • one year ago
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    111?

  11. anonymous
    • one year ago
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    idk i didn't do it hold on

  12. anonymous
    • one year ago
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    ok:)

  13. anonymous
    • one year ago
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    yeah looks good

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