PLEASE PLEASE HELP
Two quadratic functions are shown.
f(x) = 3x2 + 6x + 7 Function 2:
Which function has the least minimum value and what are its coordinates?
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
you can find the minimum value of a quadratic function by using the formula
-b/2a if we assume that the equation is given in the form y=ax^2 + bx +c
then, try to plot the values of the second function roughly on a graph paper or even a simple paper will do good with some estimation and then, you can get the answer
I dont know how to use that formula. Im new to Algebra.
okay! no problem
assume that we have a quadratic equation of the form y=ax^2 + bx + c
now, compare the equation y=ax^2 + bx + c (we call it the standard equation)
to the given equation, i.e. f(x) = 3x2 + 6x + 7
so we get a=3, b=6, c=7
now put the values of a abd b in the formula that i have specified in the above post
if you want it's derivation, i can help you with it
Not the answer you are looking for? Search for more explanations.
i think this question here just require you to input "x"
they already give they g(x) solution for various values of "x"
f(-2)=3(-2)^2+6(-2)+7..=7 .and ....g(-2)=13
f(-1)=3(-1)^2+6(-1)+7....=4 and ...g(-1)=7
f(0)=3(0)^2+6(0)+7..=7 ...and g(0)=3
f(1)=3(1)^2+6(1)+7 ...= 16 and g(1)=7
so we compare to see which function has the least minimum value..
so function 1 has the least minimum value and its coordinates are 0,7 @LynFran
no that would be function 2... with coordinate (0,3)
wow thankyou so much! @LynFran
Can u help me with more?
2)A function is shown in the table.
Which of the following is a true statement for this function?
A: The function is increasing from x=-2 to x=-1
B: The function is increasing from x=0 to x=1
C: The function is decreasing from x=-1 to x=0
D: The function is decreasing from x=0 to x=1