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anonymous
 one year ago
transform the following polar equation into an equation in rectangular coordinates r=4 sin theta
would it be x^2(y+2)^2=4?
anonymous
 one year ago
transform the following polar equation into an equation in rectangular coordinates r=4 sin theta would it be x^2(y+2)^2=4?

This Question is Closed

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3\(r = 4\sin\theta\) is a circle

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3the graph wont change between polar and cartesian

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3does your equation look anything like the eqn of a circle ?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3aren't you just guessing the options ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Remember \[x = r \cos \theta\]\[y= r \sin \theta\]\[r^2 = x^2+y^2 \implies r = \sqrt{x^2+y^2}\]

ParthKohli
 one year ago
Best ResponseYou've already chosen the best response.1Multiply both sides by \(r\) to see it.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how would I plug in the numbers though?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[r^2 = 4rsin \theta \] doing as parth suggested, see what you can do with this given the information above.

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3\[\color{red}{r^2} = 4\color{blue}{r\sin\theta}\] you don't want to see \(r, \theta\) so replace \(\color{red}{r^2} \) by \(\color{red}{x^2+y^2} \) and \(\color{blue}{r\sin\theta}\) by \(\color{blue}{y}\) just algebra circus

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0therefore X+Y=4? I get it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[x^2+y^2=4y\] \[r^2 = x^2+y^2~~~~y = r \sin \theta\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0And then from there you just substitute right?

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3technically we're done with the transformation \(x^2+y^2=4y\) is the corresponding rectangular equation are you given options or something ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I was right actually because x^2(y+2)^2=4 was correct

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3you're correct upto a + sign

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.3completing the square gives you \(x^2\color{red}{+}(y+2)^2=4\) which is slightly different from \(x^2(y+2)^2=4\) lexically, but totally different semantically. you might think "its just a +"... graph each of them and see

Jhannybean
 one year ago
Best ResponseYou've already chosen the best response.1\[x^2+y^2=4y\]\[x^2+(y^2+4y)=0\]\[x^2+(y^2+4y+\color{red}{4})=4\]\[\boxed{x^2+(y+2)^2 = 4}\]

triciaal
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439362067882:dw

UsukiDoll
 one year ago
Best ResponseYou've already chosen the best response.1the answer is right. The user just forgot to add the + sign during the final stages of this problem. \[x^2\color{red}{+}(y+2)^2=4 \]
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