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arindameducationusc
 one year ago
This question was asked by m friend Sopie.
I am not able to solve it. Can anyone help?
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arindameducationusc
 one year ago
This question was asked by m friend Sopie. I am not able to solve it. Can anyone help? See attachment

This Question is Closed

triciaal
 one year ago
Best ResponseYou've already chosen the best response.2not in order and may be incomplete ABC =180 60 = 120 ACB = 180 (25 + 120) = 180  145 = 35 AC = BD BDC =25 given AD = 65 DA is perpendicular to AE 65 + 25 = 90 = DAB

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0@triciaal why AC=BD?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.2BC parallel to AD Chord BC similar figures ABC and DCB

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0How BC paralll to AC? impossible

Jack1
 one year ago
Best ResponseYou've already chosen the best response.0do u have a screenshot? i cant open the document... :/

phi
 one year ago
Best ResponseYou've already chosen the best response.1there are a few ways to find angle ADC. one way: i) <CBE is an exterior angle of triangle ABC, so it equals the sum of the "opposite" angles: <CBE= <BAC + <BCA 60 = 25 + <BCA so <BCA= 6025= 35 ii) inscribed angle <ACD = 1/2 arc BC + 1/2 arc AB from part i) we can find arc BC and arc AB, and so we can find angle ACD

phi
 one year ago
Best ResponseYou've already chosen the best response.1for part (b), angle ADB is 1/2 arc AB which we know from part (a) for part (c), angle CAB= 65+25= 90 i.e. a right angle. if the inscribed angle is 90 degrees, then the chord is a diameter.

phi
 one year ago
Best ResponseYou've already chosen the best response.1in general, use the the idea that inscribed angles that subtend the same arc are equal dw:1439469998213:dw

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0i) inscribed angle <ACD = 1/2 arc BC + 1/2 arc AB from part i) we can find arc BC and arc AB, and so we can find angle ACD //This part I didnot understand

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0for part (c), angle CAB= 65+25= 90 i.e. a right angle. if the inscribed angle is 90 degrees, then the chord is a diameter. //How CAB is 90 when it is 25

phi
 one year ago
Best ResponseYou've already chosen the best response.1oops, I meant angle BAD is 90

phi
 one year ago
Best ResponseYou've already chosen the best response.1from the picture, can you find the length (in degrees) of arc BC ?

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0okay BAD, yes

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0n I cant find arc BC, let me analyse...hmmm....

phi
 one year ago
Best ResponseYou've already chosen the best response.1look for an inscribed angle that "opens" on arc BC

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0angle BDC?

phi
 one year ago
Best ResponseYou've already chosen the best response.1yes, but not useful. there is another one

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0angle BAC?

phi
 one year ago
Best ResponseYou've already chosen the best response.1yes, BAC also opens on arc BC. now we can figure out what arc BC is (it is 2 times angle BAC)

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0means 50? is there some theorem or axiom. can you tel me?

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0arc BC is 50?

phi
 one year ago
Best ResponseYou've already chosen the best response.1next, we can find angle BCA . do you follow the reasoning?

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0BCA, can we find by 18025120=35.? cauz angle ABC is 120

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0I didn't get about the arc and angle relation. I know one thing theta=L/R But never tried this one

phi
 one year ago
Best ResponseYou've already chosen the best response.1ok, but meanwhile you now know arc AB is what ?

phi
 one year ago
Best ResponseYou've already chosen the best response.1yes. now we know arc AC 70+50= 120

phi
 one year ago
Best ResponseYou've already chosen the best response.1and finally, we can find inscribed angle ADC (which opens on arc AC)

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0okay arc AC...

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0But please let me know the theorem. Send me some video link or something.... awesome....

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0Thank you @phi

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.0ADB is 35? @phi

phi
 one year ago
Best ResponseYou've already chosen the best response.1yes, both <ADB and <ACB are inscribed angles that subtend arc AB both are 1/2 of 70 degrees i.e. 35 deg.
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