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anonymous
 one year ago
Find the standard form of the equation of the parabola with a focus at (0, 2) and a directrix at y = 2.
anonymous
 one year ago
Find the standard form of the equation of the parabola with a focus at (0, 2) and a directrix at y = 2.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got: (x2)^2 = 8(y0) which simplifies to x^24x+4=8y but that is not any of my options...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0My options: y^2 = 2x y = 1/2*x2 y^2 = 8x y = 1/8*x2

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.1I'd say the answer is y = 1/8*x2

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439362508918:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thank you so much @wolf1728 and @triciaal

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0@akatyagi you are welcome from both of us @wolf1728 why ?

wolf1728
 one year ago
Best ResponseYou've already chosen the best response.1triciaal why is it y=(1/8)x^2 ?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0yes its an easy problem but i still got stuck I know the vertex is (0, 0) and y = x^2 + bx c = 0
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