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anonymous

  • one year ago

Find the standard form of the equation of the parabola with a focus at (0, 2) and a directrix at y = -2.

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  1. anonymous
    • one year ago
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    I got: (x-2)^2 = 8(y-0) which simplifies to x^2-4x+4=8y but that is not any of my options...

  2. anonymous
    • one year ago
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    My options: y^2 = 2x y = 1/2*x2 y^2 = 8x y = 1/8*x2

  3. wolf1728
    • one year ago
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    I'd say the answer is y = 1/8*x2

  4. triciaal
    • one year ago
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    |dw:1439362508918:dw|

  5. anonymous
    • one year ago
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    Thank you so much @wolf1728 and @triciaal

  6. triciaal
    • one year ago
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    @akatyagi you are welcome from both of us @wolf1728 why ?

  7. wolf1728
    • one year ago
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    triciaal why is it y=(1/8)x^2 ?

  8. triciaal
    • one year ago
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    yes its an easy problem but i still got stuck I know the vertex is (0, 0) and y = x^2 + bx c = 0

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