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anonymous
 one year ago
A SWAT team who is 10 meters away from the bus launches a tear gas that hits its wrecked window at point 2.5 meters above the ground. IF the tear gas is projected at an angle 38 degrees from the horizontal, determine its total time of flight. What is the initial velocity of the tear gas? Sketch the problem.
anonymous
 one year ago
A SWAT team who is 10 meters away from the bus launches a tear gas that hits its wrecked window at point 2.5 meters above the ground. IF the tear gas is projected at an angle 38 degrees from the horizontal, determine its total time of flight. What is the initial velocity of the tear gas? Sketch the problem.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Going to try the problem until someone helps me.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439370371073:dw

Jack1
 one year ago
Best ResponseYou've already chosen the best response.3who cares if it's right... that sketch is epic art dude! props~!!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0especially the stickman? XD

Jack1
 one year ago
Best ResponseYou've already chosen the best response.310m away = yep 2.5 high window = yep i guess we're assuming they launch the gas thing from ground level?? 38 degrees from horizontal... yep drawing looks great now, the important thing: can u solve it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0First thing I thought about this problem

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0component method. The vy= vosintheta

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I assume I'll get the magnitude? Then I'll use the formula Vy = Voy  gt ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohhh wait that's wrong

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0First thing is I need to know the ycomponent

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439371607809:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hmmm.. Do you I think I need to get the max height? (if it is possible)

Jack1
 one year ago
Best ResponseYou've already chosen the best response.3i guess final height = 2.5m initial height = 0 m max height = ?

Jack1
 one year ago
Best ResponseYou've already chosen the best response.3distance horizontal = 10m... initial speed = ?? acceleration vertical = 9.8 m/s i guess that's all we have to go on... yeah?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I posted a formula but I don't know if we can use it due to Vo is unknown too :(

Jack1
 one year ago
Best ResponseYou've already chosen the best response.3so ur going to have to rephrase the time in terms of the horizontal distance, then plug that into ur max height calc... sounds like a mess of work...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[y=Vot1/2(g)(t)^2\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okayy you have other ways I'm quite confuse

Jack1
 one year ago
Best ResponseYou've already chosen the best response.3give me 15... just have to dinner, then we'll solve

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Another viewer welcome!!

Jack1
 one year ago
Best ResponseYou've already chosen the best response.3hey dude, back so: known factors: initial height = 0 final height = 2.5m max height = ? initial distance = 0 final distance = 10m acceleration: ay = 9.8 m/s^2 ax = 0 Initial Speeds: Voy = Vo x sin 38 Vox = Vo x cos 38 Distance equations: sy = Voy * t + 1/2 ay t^2 sx = Vox * t + 1/2 ax t^2

Jack1
 one year ago
Best ResponseYou've already chosen the best response.3sx = Vox * t + 1/2 ax t^2 and ax = 0 sx = Vox * t + 0 10 = Vox * t t = 10/Vox and Vox = Vo * cos 38 so t = 10/Vox t = 10/(Vo * cos 38) sy = Voy * t + 1/2 ay t^2 2.5 = Voy * t + 1/2 ay t^2 2.5 = Voy * (10/(Vo * cos 38)) + 1/2 * 9.8 * (10/(Vo * cos 38))^2 and Voy = Vo x sin 38 so 2.5 = Voy * (10/(Vo * cos 38)) + 1/2 * 9.8 * (10/(Vo * cos 38))^2 2.5 = (Vo x sin 38) * (10/(Vo * cos 38)) + 1/2 * 9.8 * (10/(Vo * cos 38))^2

Jack1
 one year ago
Best ResponseYou've already chosen the best response.3what a freakin mouthful that is! ;D so... can you solve that in terms of Vo from here?

Jack1
 one year ago
Best ResponseYou've already chosen the best response.3ooo... also: does that make sense? any issues with those kinematic equations dude?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Nah nah I'm good will read your text first gimme a sec

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0not literally a sec but maybe longer lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait still reading and understanding

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Question about the distance equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0sy = Voy * t + 1/2 ay t^2 isn't it sy= Voy*t  1/2g(t)^2 ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0or maybe u just translate it to other terms and it is just the same

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0nvm the question I got it

Jack1
 one year ago
Best ResponseYou've already chosen the best response.3yep, its the same, i just use a for acceleration rather than g for gravity

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0in freefall ax is always 0 right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0bc there's force upon it only the ycomponent

Jack1
 one year ago
Best ResponseYou've already chosen the best response.3yep, we assume wind resistance = negligable, so no x component to acceleration

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Can you explain the logic behind putting t=10/voxcos38 in the sy=voyt+1/2ay(t)^2

Jack1
 one year ago
Best ResponseYou've already chosen the best response.3because we want an equation with only 1 unknown in it... so we put everything in terms of inital velocity (Vo  not component split) then we solve for Vo then we use that to solve for time

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02.5 = (Vo x sin 38) * (10/(Vo * cos 38)) + 1/2 * 9.8 * (10/(Vo * cos 38))^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0isn't it that vo is also vox you just forgot to put x on it?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay we're finding vox after this

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no wait vox = 10 right?

Jack1
 one year ago
Best ResponseYou've already chosen the best response.3no, we're finding Vo Vox is the x component (horizontal component) of Vo we just want Vo

Jack1
 one year ago
Best ResponseYou've already chosen the best response.32.5 = (Vo * sin 38) * (10/(Vo * cos 38)) + 1/2 * 9.8 * (10/(Vo * cos 38))^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Okay moving on after I got Vo Ill use this?

Jack1
 one year ago
Best ResponseYou've already chosen the best response.3just solve Vo first then put that back into t = 10/(Vo * cos 38) to solve for t then... well ... done, yeah? ur time in flight equation assumes the start and finish height are the same... so it wont work for this question

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The question is quite odd I thought we need to find the T first before Vo. But ohwell what works.. works

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ohmy I thought we are done. Sorry!! Forgive me. Wait a sec I'll solve

Jack1
 one year ago
Best ResponseYou've already chosen the best response.3lol, sçool, jus wanna make sure we get the same answers for Vo and t, s'all ;)

Jack1
 one year ago
Best ResponseYou've already chosen the best response.3perfect (+ or ... and minus is insane, so answer is positive 12.1871) now t?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01.0412 well that was fast

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0such a skilled swat team LOL

Jack1
 one year ago
Best ResponseYou've already chosen the best response.3for a grenade... psh, not that fast like olympic sprinters = 100m in sub ten seconds... so yeah... sprint speed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well if you think of it under pressure and you're throwing it in a window! Such accuracy

Jack1
 one year ago
Best ResponseYou've already chosen the best response.3totes well, i'm out, catchya dude, u cool with all that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Of course thankyou!! U have yourself a new fan :D

Jack1
 one year ago
Best ResponseYou've already chosen the best response.3logend, no worries bro, slaters ;P
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