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Going to try the problem until someone helps me.
is my sketch right?
who cares if it's right... that sketch is epic art dude! props~!!!
especially the stickman? XD
10m away = yep 2.5 high window = yep i guess we're assuming they launch the gas thing from ground level?? 38 degrees from horizontal... yep drawing looks great now, the important thing: can u solve it?
First thing I thought about this problem
component method. The vy= vosintheta
I assume I'll get the magnitude? Then I'll use the formula Vy = Voy - gt ?
Ohhh wait that's wrong
First thing is I need to know the y-component
Hmmm.. Do you I think I need to get the max height? (if it is possible)
i guess final height = 2.5m initial height = 0 m max height = ?
distance horizontal = 10m... initial speed = ?? acceleration vertical = -9.8 m/s i guess that's all we have to go on... yeah?
I posted a formula but I don't know if we can use it due to Vo is unknown too :(
so ur going to have to rephrase the time in terms of the horizontal distance, then plug that into ur max height calc... sounds like a mess of work...
Okayy you have other ways I'm quite confuse
give me 15... just have to dinner, then we'll solve
Will do. :D
Another viewer welcome!!
hey dude, back so: known factors: initial height = 0 final height = 2.5m max height = ? initial distance = 0 final distance = 10m acceleration: ay = -9.8 m/s^2 ax = 0 Initial Speeds: Voy = Vo x sin 38 Vox = Vo x cos 38 Distance equations: sy = Voy * t + 1/2 ay t^2 sx = Vox * t + 1/2 ax t^2
sx = Vox * t + 1/2 ax t^2 and ax = 0 sx = Vox * t + 0 10 = Vox * t t = 10/Vox and Vox = Vo * cos 38 so t = 10/Vox t = 10/(Vo * cos 38) sy = Voy * t + 1/2 ay t^2 2.5 = Voy * t + 1/2 ay t^2 2.5 = Voy * (10/(Vo * cos 38)) + 1/2 * -9.8 * (10/(Vo * cos 38))^2 and Voy = Vo x sin 38 so 2.5 = Voy * (10/(Vo * cos 38)) + 1/2 * -9.8 * (10/(Vo * cos 38))^2 2.5 = (Vo x sin 38) * (10/(Vo * cos 38)) + 1/2 * -9.8 * (10/(Vo * cos 38))^2
what a freakin mouthful that is! ;D so... can you solve that in terms of Vo from here?
ooo... also: does that make sense? any issues with those kinematic equations dude?
Nah nah I'm good will read your text first gimme a sec
not literally a sec but maybe longer lol
wait still reading and understanding
Question about the distance equation
sy = Voy * t + 1/2 ay t^2 isn't it sy= Voy*t - 1/2g(t)^2 ??
or maybe u just translate it to other terms and it is just the same
nvm the question I got it
yep, its the same, i just use a for acceleration rather than g for gravity
in freefall ax is always 0 right?
bc there's force upon it only the y-component
yep, we assume wind resistance = negligable, so no x component to acceleration
Can you explain the logic behind putting t=10/voxcos38 in the sy=voyt+1/2ay(t)^2
because we want an equation with only 1 unknown in it... so we put everything in terms of inital velocity (Vo - not component split) then we solve for Vo then we use that to solve for time
2.5 = (Vo x sin 38) * (10/(Vo * cos 38)) + 1/2 * -9.8 * (10/(Vo * cos 38))^2
isn't it that vo is also vox you just forgot to put x on it?
okay we're finding vox after this
no wait vox = 10 right?
no, we're finding Vo Vox is the x component (horizontal component) of Vo we just want Vo
sx = 10
moving on I get it
2.5 = (Vo * sin 38) * (10/(Vo * cos 38)) + 1/2 * -9.8 * (10/(Vo * cos 38))^2
Okay moving on after I got Vo Ill use this?
just solve Vo first then put that back into t = 10/(Vo * cos 38) to solve for t then... well ... done, yeah? ur time in flight equation assumes the start and finish height are the same... so it wont work for this question
I forgot about that
The question is quite odd I thought we need to find the T first before Vo. But ohwell what works.. works
focus dude, solve Vo
Ohmy I thought we are done. Sorry!! Forgive me. Wait a sec I'll solve
lol, sçool, jus wanna make sure we get the same answers for Vo and t, s'all ;)
I got vo=12.1871
perfect (+ or -... and minus is insane, so answer is positive 12.1871) now t?
1.0412 well that was fast
such a skilled swat team LOL
for a grenade... psh, not that fast like olympic sprinters = 100m in sub ten seconds... so yeah... sprint speed
well if you think of it under pressure and you're throwing it in a window! Such accuracy
totes well, i'm out, catchya dude, u cool with all that?
Of course thankyou!! U have yourself a new fan :D
logend, no worries bro, slaters ;P