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Abhisar
 one year ago
How many coordinate bonds are there in \(\sf SO_3\) molecule and how?
Why \(\sf SO_3\) has 2 dative bonds?
Abhisar
 one year ago
How many coordinate bonds are there in \(\sf SO_3\) molecule and how? Why \(\sf SO_3\) has 2 dative bonds?

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Abhisar
 one year ago
Best ResponseYou've already chosen the best response.7Got it, i'll leave a reply in case any body looks up. Let's draw lewis dot structure of \(\sf SO_3\) first. dw:1439384639045:dw

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.7There are only 6 electrons in the valence shell of sulfur so it can make one more bond with any of the one oxygen atom. dw:1439384821543:dw

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.7dw:1439385110913:dw If we check formal charges on the atoms, we see that \(\sf O_1\) has 0 FC \(\sf O_2\) and \(\sf O_3\) has 1 each and sulfur has a +2 FC. These appear to be quite high formal charges so there must be another structure which will be more stable. Also, we know that sulfur is a period 3 element and hence it can have more than 8 (upto 12)electrons in its outer valence shell due to the presence of vacant 3d orbitals. So sulfur will form 2 dative bonds with the rest of two oxygen atom.

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.7dw:1439385229312:dw Also note that formal charge on each of the atoms is 0 now which means it's very stable structure.

Abhisar
 one year ago
Best ResponseYou've already chosen the best response.7PS: In some books you will find rigorous implementation of octet rule on sulfur. In that case there will be a total of 1 double bond and 2 dative bonds. dw:1439439046279:dw
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