## xmistermayhem one year ago An engineer is surveying a building with a device that is 6 feet above the ground. He is 60 feet from the building and is looking with an angle of elevation of 45°. How tall is the building? ... I'm really bad at trig. x....x

1. anonymous

start by drawing a picture. what do you think this scenario looks like?

2. sohailiftikhar

|dw:1439384614923:dw|

3. sohailiftikhar

$\tan \theta = x/60$

4. xmistermayhem

What about the 6 feet, though?

5. sohailiftikhar

nothing we will add after knowing the value of x

6. xmistermayhem

Oh okay Uhhh... How do you find that? What does θ mean?

7. sohailiftikhar

|dw:1439384809225:dw|

8. sohailiftikhar

$\theta=45$

9. xmistermayhem

So whatever x is + 6 = the height of the building?

10. sohailiftikhar

yes! you got it buddy

11. xmistermayhem

so tan 45 degrees = x/60 ?

12. sohailiftikhar

it's 66 feet

13. sohailiftikhar

yes

14. xmistermayhem

Ohhh okay Thank you!!! I think I got it now!! : )