xmistermayhem
  • xmistermayhem
An engineer is surveying a building with a device that is 6 feet above the ground. He is 60 feet from the building and is looking with an angle of elevation of 45°. How tall is the building? ... I'm really bad at trig. x....x
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
start by drawing a picture. what do you think this scenario looks like?
sohailiftikhar
  • sohailiftikhar
|dw:1439384614923:dw|
sohailiftikhar
  • sohailiftikhar
\[\tan \theta = x/60\]

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xmistermayhem
  • xmistermayhem
What about the 6 feet, though?
sohailiftikhar
  • sohailiftikhar
nothing we will add after knowing the value of x
xmistermayhem
  • xmistermayhem
Oh okay Uhhh... How do you find that? What does θ mean?
sohailiftikhar
  • sohailiftikhar
|dw:1439384809225:dw|
sohailiftikhar
  • sohailiftikhar
\[\theta=45\]
xmistermayhem
  • xmistermayhem
So whatever x is + 6 = the height of the building?
sohailiftikhar
  • sohailiftikhar
yes! you got it buddy
xmistermayhem
  • xmistermayhem
so tan 45 degrees = x/60 ?
sohailiftikhar
  • sohailiftikhar
it's 66 feet
sohailiftikhar
  • sohailiftikhar
yes
xmistermayhem
  • xmistermayhem
Ohhh okay Thank you!!! I think I got it now!! : )

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