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xmistermayhem
 one year ago
An engineer is surveying a building with a device that is 6 feet above the ground. He is 60 feet from the building and is looking with an angle of elevation of 45°. How tall is the building? ... I'm really bad at trig. x....x
xmistermayhem
 one year ago
An engineer is surveying a building with a device that is 6 feet above the ground. He is 60 feet from the building and is looking with an angle of elevation of 45°. How tall is the building? ... I'm really bad at trig. x....x

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0start by drawing a picture. what do you think this scenario looks like?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439384614923:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\tan \theta = x/60\]

xmistermayhem
 one year ago
Best ResponseYou've already chosen the best response.0What about the 6 feet, though?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0nothing we will add after knowing the value of x

xmistermayhem
 one year ago
Best ResponseYou've already chosen the best response.0Oh okay Uhhh... How do you find that? What does θ mean?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439384809225:dw

xmistermayhem
 one year ago
Best ResponseYou've already chosen the best response.0So whatever x is + 6 = the height of the building?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes! you got it buddy

xmistermayhem
 one year ago
Best ResponseYou've already chosen the best response.0so tan 45 degrees = x/60 ?

xmistermayhem
 one year ago
Best ResponseYou've already chosen the best response.0Ohhh okay Thank you!!! I think I got it now!! : )
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