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anonymous
 one year ago
The sled dog must produce a horizontal force of 80 N in order to keep the 160 kg sled moving across level ice at a constant velocity. What is the coefficient of kinetic friction between the sled and the ice?
anonymous
 one year ago
The sled dog must produce a horizontal force of 80 N in order to keep the 160 kg sled moving across level ice at a constant velocity. What is the coefficient of kinetic friction between the sled and the ice?

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok so the part that confuses me the most is "constant velocity" meaning that there is inertia at work.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I am not too sure if I can just use the given values to go with the kinetic friction....Any ideas people?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The constant velocity part is just another way of saying it's in equilibrium. dw:1439385917192:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I bet the coefficient of friction in this case must be 0.5

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0As 80N are required to move an object that weights 160kg

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0By constant velocity they mean that acceleration is 0, and therefore there is no resultant force on the sled, then the force applied by the dog is just enough to balance friction \[\implies f=80N\] taking the direction of motion of sled as positive direction, then friction will work in opposite direction Now we know that \[f=\mu.N\]\[\mu=\frac{f}{N}\]\[\mu=\frac{80}{160 \times 9.8}=\frac{80}{160 \times 9.8}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no. the frictional force must balance the applied force for equilibrium. \[mg \mu_k=80~ N\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Looks like the second explanation is right.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It is. they're the same. I was replying to the 0.5 response and we posted at about the same time.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So according to the calculation kinetic friction is revealed as 0.05

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Well that seems pretty low but I guess that's how much kinetic friction is required for the dog to just apply 80N force and have the sled moving ahead.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The low coefficient of friction makes sense because 1) the surface is ice and 2) the coefficient of kinetic friction is generally less than the coefficient of static friction because it takes more force to make something move than it does to keep it moving.
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