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anonymous
 one year ago
u = 4i + 1j and v = 4i + 1j; Find .u+V the answer is u+v=2j
anonymous
 one year ago
u = 4i + 1j and v = 4i + 1j; Find .u+V the answer is u+v=2j

This Question is Closed

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0my teacher siad i was wrong

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0\(\u+v\\) represents the length of vector \(u+v\)

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0what you had there is just the vector \(u+v\) but your teacher wants its length

ganeshie8
 one year ago
Best ResponseYou've already chosen the best response.0how does vector 2j look ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You are already given where vector u and vector v are pointing at, the distance between these points can be found using distance formula

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait sorry nevermind I messed up, forget that figure ok

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0for a vector \[\vec a=x \hat i+y \hat j+z \hat k\] It's magnitude is given by \[\vec a=a=\sqrt{x^2+y^2+z^2}\] so for \[\vec u + \vec v=\sqrt{?^2+?^2+?^2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0your vector \[\vec u + \vec v =0\hat i+2\hat j+0\hat k\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im so counfuzzled this is why i dont do math lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok I will try to explain

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439388825827:dw \[\vec a=x \hat i+y \hat j\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You can think of it has moving x amount along xaxis(in the direction of i hat) and moving y units along yaxis (in the direction of j hat)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you understand this much?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Now consider the triangle dw:1439389090592:dw How can you solve for the question mark?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's a right triangle

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0umm i needa find the ? how do i do that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yep, remember the good ol pythagorus thm?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i do put i never could do it properly

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439389330955:dw\[c^2=a^2+b^2\] \[c=\sqrt{a^2+b^2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Then if your sides are of x and y length, then what will be the "c" in that case?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0instead of a and b, we have x and y

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im there im thinking

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0idk lol why am i supose to be doing sorry i have had no sleep

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439389871725:dw\[?=\sqrt{x^2+y^2}\] Does that make sense?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok so that question mark is the hypotenuse of the triangle so if we consider... dw:1439389973299:dw Then that question mark indeed tells us the length of the vector

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0we have to do all this to get to the answer lol i think imma pass out

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0That is to say for a vector \[\vec a =x \hat i+y \hat j\] It's magnitude is given by \[\vec a=a=\sqrt{x^2+y^2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No the question is really short, I'm doing all this so u can understand it !!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439390177628:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what is all that lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0your vector \[\vec u +\vec v=0 \hat i +2 \hat j\] Compare it to the form \[\vec a = x \hat i +y \hat j\] You find that \[x=0\]\[y=2\] then the magnitude is given by \[\vec u +\vec v=\sqrt{x^2+y^2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0you just have to take the squares of all the components of vector and add them then take their square root to find the lengh of a vector

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i just wanna be done with this question i have three more questions lol

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0umm me and my tutor got that answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I'm sorry but there's nothing I can do about that. I've really tried to dumb it down as much as possible, sorry if you can't understand, everyone learns in a different way. If you're not sure about pythagorus theorem, you should clear your concept about that before attempting vectors

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh! lol it was answer of v+u i thought it was the answer of \[\left v+u \right\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so are we done here or what
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