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anonymous

  • one year ago

u = -4i + 1j and v = 4i + 1j; Find .||u+V|| the answer is u+v=2j

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  1. anonymous
    • one year ago
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    my teacher siad i was wrong

  2. ganeshie8
    • one year ago
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    \(\|u+v\|\) represents the length of vector \(u+v\)

  3. ganeshie8
    • one year ago
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    what you had there is just the vector \(u+v\) but your teacher wants its length

  4. anonymous
    • one year ago
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    ohh ok

  5. ganeshie8
    • one year ago
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    how does vector 2j look ?

  6. anonymous
    • one year ago
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    You are already given where vector u and vector v are pointing at, the distance between these points can be found using distance formula

  7. anonymous
    • one year ago
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    how do i do that

  8. anonymous
    • one year ago
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    wait sorry nevermind I messed up, forget that figure ok

  9. anonymous
    • one year ago
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    for a vector \[\vec a=x \hat i+y \hat j+z \hat k\] It's magnitude is given by \[|\vec a|=a=\sqrt{x^2+y^2+z^2}\] so for \[|\vec u + \vec v|=\sqrt{?^2+?^2+?^2}\]

  10. anonymous
    • one year ago
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    your vector \[\vec u + \vec v =0\hat i+2\hat j+0\hat k\]

  11. anonymous
    • one year ago
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    im so counfuzzled this is why i dont do math lol

  12. anonymous
    • one year ago
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    ok I will try to explain

  13. anonymous
    • one year ago
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    |dw:1439388825827:dw| \[\vec a=x \hat i+y \hat j\]

  14. anonymous
    • one year ago
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    You can think of it has moving x amount along x-axis(in the direction of i hat) and moving y units along y-axis (in the direction of j hat)

  15. anonymous
    • one year ago
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    Do you understand this much?

  16. anonymous
    • one year ago
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    so far

  17. anonymous
    • one year ago
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    Now consider the triangle |dw:1439389090592:dw| How can you solve for the question mark?

  18. anonymous
    • one year ago
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    It's a right triangle

  19. anonymous
    • one year ago
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    umm i needa find the ? how do i do that

  20. anonymous
    • one year ago
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    Yep, remember the good ol pythagorus thm?

  21. anonymous
    • one year ago
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    i do put i never could do it properly

  22. anonymous
    • one year ago
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    |dw:1439389330955:dw|\[c^2=a^2+b^2\] \[c=\sqrt{a^2+b^2}\]

  23. anonymous
    • one year ago
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    remember that?

  24. anonymous
    • one year ago
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    yes i do

  25. anonymous
    • one year ago
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    Then if your sides are of x and y length, then what will be the "c" in that case?

  26. anonymous
    • one year ago
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    instead of a and b, we have x and y

  27. anonymous
    • one year ago
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    you there bro?

  28. anonymous
    • one year ago
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    im there im thinking

  29. anonymous
    • one year ago
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    ok

  30. anonymous
    • one year ago
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    idk lol why am i supose to be doing sorry i have had no sleep

  31. anonymous
    • one year ago
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    |dw:1439389871725:dw|\[?=\sqrt{x^2+y^2}\] Does that make sense?

  32. anonymous
    • one year ago
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    yess captin

  33. anonymous
    • one year ago
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    Ok so that question mark is the hypotenuse of the triangle so if we consider... |dw:1439389973299:dw| Then that question mark indeed tells us the length of the vector

  34. anonymous
    • one year ago
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    we have to do all this to get to the answer lol i think imma pass out

  35. anonymous
    • one year ago
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    That is to say for a vector \[\vec a =x \hat i+y \hat j\] It's magnitude is given by \[|\vec a|=a=\sqrt{x^2+y^2}\]

  36. anonymous
    • one year ago
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    No the question is really short, I'm doing all this so u can understand it !!

  37. anonymous
    • one year ago
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    ok lol

  38. anonymous
    • one year ago
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    |dw:1439390177628:dw|

  39. anonymous
    • one year ago
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    what is all that lol

  40. anonymous
    • one year ago
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    your vector \[\vec u +\vec v=0 \hat i +2 \hat j\] Compare it to the form \[\vec a = x \hat i +y \hat j\] You find that \[x=0\]\[y=2\] then the magnitude is given by \[|\vec u +\vec v|=\sqrt{x^2+y^2}\]

  41. sohailiftikhar
    • one year ago
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    you just have to take the squares of all the components of vector and add them then take their square root to find the lengh of a vector

  42. anonymous
    • one year ago
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    i just wanna be done with this question i have three more questions lol

  43. anonymous
    • one year ago
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    umm me and my tutor got that answer

  44. anonymous
    • one year ago
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    I'm sorry but there's nothing I can do about that. I've really tried to dumb it down as much as possible, sorry if you can't understand, everyone learns in a different way. If you're not sure about pythagorus theorem, you should clear your concept about that before attempting vectors

  45. sohailiftikhar
    • one year ago
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    oh! lol it was answer of v+u i thought it was the answer of \[\left| v+u \right|\]

  46. anonymous
    • one year ago
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    yeah

  47. anonymous
    • one year ago
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    so are we done here or what

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