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my teacher siad i was wrong

\(\|u+v\|\) represents the length of vector \(u+v\)

what you had there is just the vector \(u+v\)
but your teacher wants its length

ohh ok

how does vector 2j look ?

how do i do that

wait sorry nevermind I messed up, forget that figure ok

your vector
\[\vec u + \vec v =0\hat i+2\hat j+0\hat k\]

im so counfuzzled this is why i dont do math lol

ok I will try to explain

|dw:1439388825827:dw|
\[\vec a=x \hat i+y \hat j\]

Do you understand this much?

so far

Now consider
the triangle
|dw:1439389090592:dw|
How can you solve for the question mark?

It's a right triangle

umm i needa find the ? how do i do that

Yep, remember the good ol pythagorus thm?

i do put i never could do it properly

|dw:1439389330955:dw|\[c^2=a^2+b^2\]
\[c=\sqrt{a^2+b^2}\]

remember that?

yes i do

Then if your sides are of x and y length, then what will be the "c" in that case?

instead of a and b, we have x and y

you there bro?

im there im thinking

ok

idk lol why am i supose to be doing sorry i have had no sleep

|dw:1439389871725:dw|\[?=\sqrt{x^2+y^2}\]
Does that make sense?

yess captin

we have to do all this to get to the answer lol i think imma pass out

No the question is really short, I'm doing all this so u can understand it !!

ok lol

|dw:1439390177628:dw|

what is all that lol

i just wanna be done with this question i have three more questions lol

umm me and my tutor got that answer

oh! lol it was answer of v+u i thought it was the answer of \[\left| v+u \right|\]

yeah

so are we done here or what