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anonymous
 one year ago
Physics;accounting for tension of a pulley on frictionless surface.
anonymous
 one year ago
Physics;accounting for tension of a pulley on frictionless surface.

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Tension of the pulley is calculated using........

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2newtons laws of motion

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2applying newtons law to the whole system force = mass * acceleration 6*g = 11 * a a = 6*9.8 /11 = 5.35 m s2

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2now i know how to find the tension in the string considering the horizontal string applying newtons second law; Tension = 10 * 5.35 = 53. 5 N

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2but you require tension in the pulley right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think its mg= 6*9.8=tension on the string since the is no effect of 5 kg wt. as surface is frictionless

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2sorry i dont know where i got 10 from!!!!

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2if you consider the horizontal string its 5 * 5.35 not 10 * 5.35

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2hhmm.. i'm not sure I would have thought you would have to take the 5 kg into account. Its been a long time since i did these...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@welshfella how can you add 6+5= 11 to get 11*a this is not the case actually...

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2but i'mm considering the whole system 5 kg and 6 kg are part of the whole system

welshfella
 one year ago
Best ResponseYou've already chosen the best response.26 g is the downward force (dues to 6 kg mass) but 5kg is part of the mass

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2the tension will be the same throughout the whole string so i guess thats also the force on the pulley

anonymous
 one year ago
Best ResponseYou've already chosen the best response.05kg would have created friction on the surface due to wt. which would hav then created a resistance to allow the whole system to move down....this would hav decreased the tension on the string but here the surface is frictionless...

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2hmm maybe but i dont think you can ignore the 5 kg...

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2I'd have to look it up

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439391345545:dw

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2https://www.youtube.com/watch?v=e2yHHSzjTs  this is about a similar problem

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0no effect of the 2 forces on each other due to surface is frictionless...

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2if you check out the above link you'll see i'm right The 5kg has to be taken into account

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2there is a tension between the 2 masses  the tension in the string

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0may be you are right....i got confused...i hav to think again on it....

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2its a tricky subject I wasn't sure but the link gives a good explanation.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@welshfella yes your were right....i hav checked my book...my doubt is cleared....i am sorry that i wasted your time....but thanks....

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2No you didn't waste my time  I had to make sure I was right also!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Hey guys thanks for all your insights

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This kind is one of the most counterintuitive

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Therefore so far to our best of knowledge tension 11kg*5.35m/^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I am crying right now

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2yes  its s a bit hard to visualive  If the mass of the object on the table was say 15 kg there would still be motion because the table is frictionlass

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0according to inertia that is.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So it naturally falls upon us to calculate the acceleration and corresponding weight of the whole system

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Because tension is responsible for holding two masses which sum up to kg. Tension holds them from falling apart after all. Given that one side of the tension is pulling the system both masses are involved in the motion of the whole system.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0You established that "connection" with me here. Universal law of affection of physics applies to all of usXD

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2we've found that the acceleration is 5.35 m s2 but now we have to find the tension

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Isn't the tension 11kg*5.35m/s^2?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0But tension on the pulley... I don't know

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that's the hardest part of this question is "tension on the pulley" instead of tension of the line.

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2well the units of the tension will be N Newtons

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2* will be in Newtons

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0see what i hav checked in my book, (m1+m2)a = m2*g T= m2*g  m2*a

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2yea that looks good

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Your equation assumes that overall force required to move the entire system is equivalent to the force exerted by a mass due to gravity.... Ok. This holds true on frictionless surface I suppose.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0*overall force required to accelerate

anonymous
 one year ago
Best ResponseYou've already chosen the best response.011*5.35m/s^2 assumes normal force is ignored?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2yes normal force acts perpendicular to motion so can be ignored

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0No I think you should consider the "tension" which is induced by the 6kg mass as well. To assume there is only 5kg being responsible for the tension is absurd because it's not the only factor pulling the line.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@welshfella got you .

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0People say he's a physicist so

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2can we apply newtons second law to the 5 kg mass in isolation? in which case we can say T = 5 * 5.35 = 26.75 N ?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2 why can't we do that?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2 that gives the tension in the horizontal string

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The prospect of assuming the tension to be "stretched" is somehow absurd?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I think that reason why 6kg object is considered is because it's the source of force.

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2I'll have to look at another video lol! I'm not saying you guys are wrong but i'm not convinced.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@welshfella you are right T= 5 * 5.35 N

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2I;ll give you a medal for saying that lol!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0So it's not the initial 11kg*5.35m/s^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but rather the second one.

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2I'd like to giv medal to Robert also but it wont let me...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that is final @welshfella is right...

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Thanks so much physics aficionados I think I understand it now.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Robert136 do you got it?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2yea the more i think about it.... the horizontal tension pulls the 5 kg mass so T must = mass * a = 5 * 5.35

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the more I think about it the better it settles in my brainXD

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2but thats the tension in string what about the pulley? T acts directly on the pulley so that makes T on pulley = 26.75 N also?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Right the tension is essentially moving the 5kg mass on frictionless surface so the tension must only account for the 5kg and greater acceleration implies proportionally valid force being applied. Ha! I think that's our ultimatum

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@welshfella your above statement is true...

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2well guys we've learnt something with this session Good

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The pulley is more like the center of this system at 90 degree angle. What if it was 180 degrere angle we all know to be the same?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Since frictionless the direction must not matter ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Mechanical advantage says it takes one half of force if pulley is used in two fold like manner. But I guess this doesn't concern this partiuclar problem...

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2Its coming back to me now  after all these years  I wont say how many (lol!!)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Physics is the protein bar for the intelligence

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Where intuition fails all the time. problem of this kind makes me reflect on my life from more logical poin of view.

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2the pulley must also be frictionless for the tension throughout the string to be uniform

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0uniform acceleration that is

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Where veocity time graph would have a positive slope.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Do you remember that stuff??

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2some of it yes acceleration = rate of change of velocity = slope

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2and distance traveled = area under the graph

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2uniform velocity is indicated by a straight line with a positive slope

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2* sorry that's uniform acceleration

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah whereas friction would prevent that

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0One quick recap on this thread; when we did the calculation on acceleration of the whole system we used the sum of both masses.... is that accurate?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0As in 6.0kg*9.8m/s^2=11a as opposed to 5a just like what we did in the last counterpart.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0The object being acted upon is the 5.0kg mass accelerating... hmm my brain is such a pelletty equipment.

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2yes we dealt with the whole system as we have no friction it was just like everything was horizontal with the force of gravity 6g acting on whole system and a weightless rigid body connecting the 2 masses

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2dw:1439398166592:dw

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2the double arrows indicate acceleration

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2the force acting is 6g mass * acceleration due to gravity

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Ok. I get it. But how's that related to having only the 6kg object as being responsible for the entire system? I feel like 5.0kg is being "pulled" rather than moving "together" with the 6.0kg object. HmmmI guess I am really dumb

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2the force has to accelerate the total mass which is 11 kg

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2yes the 5 kg is being pulled by the tension in the string which is caused by the downward force of the 6 kg weight. I f there was no weight on the table the acceleration would be much greater . The 5 kg slows the whole system down. bit it is part of the system .

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2If its weight was say 50 kg the system would still be in motion but acceleration would be a lot less.

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2It is intuitive to a degree because the heavier the mass the acceleration would be a lot slower  because the force is constant at 6 g N but the mass is greater

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2you can also find the tension in the string by considering the mass of 6 kg without referring to the 5 kg dw:1439398934381:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Tension can be calculated with 6kg using the acceleratoin?

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2the tension is working against the force 6g so the net force = 6g  T applying the second law 6*9.81  T = 6 * 5.35 T = 26.76 N

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2yes its valid to consider both masses separately

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2in fact we could have found T and a by using 2 system of equations 6.g  T = 6 a  for the g kg mass T = 5a  for the 5 kg mass

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2so we could have found T and a together

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2adding we get 6g = 11a a = 6g/11 = 5.35 then T = 5 8 5.35 = 26.75

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2its all coming back now

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0We all strive to find that momentXD Nostalgia old schoolXD

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2Yea we had a very good math teacher. Our school was a very good one one  in Swansea UK. II guess its most famous pupil was Dylan Thomas the poet

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Awesome! I miss going to american schools:)

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2Not that he was any good at Math. He was exceptional at English and cared nothing about anything else.

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2yea At the time you didn't realize how good those days were.

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2Have you ever heard recordings of Dylan Thomas reciting poetry? Some people don't like the way he reads them others find it awesome.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Dylan Thomas don't gentle into that good night. Old age should rage at close of day. Rage rage rage into that good night.

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2yea that's his most famous poem.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0It's so true though.

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2Well id better feed the cat. She's in charge!! Yes. His father was the English teacher in the school and its to him the poem was written.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Yeah every time I read his poem it makes me regret and realize so much I missed in life

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I guess I am supposed to be raging and raving but every day seems o be the reality of inevitable time passing.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I wish I could have more emotions at work and assign a meaning to every day each day until I die. I guess travelling seems to be the best option for all of us.

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2I think we waste a lot of time thinking about what we are going to do but never do it. Yea If you can afford it travel is great.

welshfella
 one year ago
Best ResponseYou've already chosen the best response.2nice talking to you must go

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Likewise! Thank so much for your help:) See you around.
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