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anonymous

  • one year ago

First time. Help! Solve the following system of equations and show all work: y=x^2+3 y=x+5

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  1. anonymous
    • one year ago
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    y=x^2+3 y=x+5 We can do this x^2 + 3 = x + 5 x^2 - x + 3 - 5 = 0 x^2 - x - 2 = 0 Now , solve this equation for x .

  2. anonymous
    • one year ago
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    so would it be 2x-x-2=0 x-2=0 x=2?

  3. anonymous
    • one year ago
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    (x-2)(x+1) = 0 X-2 = 0 or x + 1 = 0 so x is either -1 or 2

  4. anonymous
    • one year ago
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    What are the options?

  5. anonymous
    • one year ago
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    there are no options

  6. anonymous
    • one year ago
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    Are we suppose to find y also?

  7. anonymous
    • one year ago
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    i don't know. it's not a multiple choice question :/ it just say solve the system of equations

  8. phi
    • one year ago
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    x= -1 or x=2 use those numbers to find the corresponding y in y=x+5

  9. phi
    • one year ago
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    this problem has two solutions i.e. two (x,y) points that lie on both the line and the parabola.

  10. anonymous
    • one year ago
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    so it doesn't matter which x i use ?

  11. phi
    • one year ago
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    you use both, one at a time. you want to find two (x,y) pairs where x is -1 in the first pair (and you need to find the y) and x=2 in the other pair

  12. anonymous
    • one year ago
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    so it would be (-1,4) or (2,7)

  13. anonymous
    • one year ago
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    Yes.

  14. anonymous
    • one year ago
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    what do i do about the other y equation?

  15. phi
    • one year ago
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    you could use either equation to find y but it makes sense to use the easier one. you are done! btw, here is what you found... where the line meets the parabola

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  16. anonymous
    • one year ago
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    okay. thank you both so much! how do i give you both medals for helping me out?

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