anonymous
  • anonymous
any help for a fan and meadal
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
What do you need help with?
anonymous
  • anonymous
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anonymous
  • anonymous
I don't remember this on wait what lesson is this

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anonymous
  • anonymous
does not say
anonymous
  • anonymous
@ChiefArnav
anonymous
  • anonymous
well I think its p so
anonymous
  • anonymous
okay thanks
anonymous
  • anonymous
np
anonymous
  • anonymous
@ganeshie8
anonymous
  • anonymous
Triangle P is not unique
anonymous
  • anonymous
then what is it
anonymous
  • anonymous
I would say it would be triangle Q, since there can be 55 degree angles in more than one triangle
anonymous
  • anonymous
oh
anonymous
  • anonymous
@aszarek8999 what do you think?
jjamz87
  • jjamz87
It's triangle q
mathstudent55
  • mathstudent55
A. Triangle P: all side lengths are given. This reminds us of SSS. Therefore, it must be a unique triangle.
anonymous
  • anonymous
I still think it's P but I'm gonna take another look
anonymous
  • anonymous
okay
anonymous
  • anonymous
I am pretty sure it is triangle Q
mathstudent55
  • mathstudent55
C. Two sides and an included angle are given. This reminds us of SAS. Once again, this triangle is unique.
anonymous
  • anonymous
It would help if i had read the question right!
anonymous
  • anonymous
ts definitly triangle Q
mathstudent55
  • mathstudent55
D. We are given a base and two base angles. This means ASA. Once again, this triangle is unique.
anonymous
  • anonymous
so what is it
mathstudent55
  • mathstudent55
By the process of elimination, the answer must be B., but let's look at it to see why. In B. we are given only 2 angles. Two angles reminds us of AA Similarity. We can only prove triangles similar with AA Similarity. There is an infinite number of triangles with 2 given angles since the sides can by any lengths.
anonymous
  • anonymous
kk thanks
mathstudent55
  • mathstudent55
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