LifeIsADangerousGame
  • LifeIsADangerousGame
Can anyone give me an explanation for this? http://cdn2.hubspot.net/hub/360031/hubfs/body_arithmetic-1.jpg?t=1439394385622&width=504
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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ganeshie8
  • ganeshie8
\(n^2\ge 1\tag{1}\) \(\implies |n| \ge 1\) \( \implies n^2\ge n\tag{2}\) adding both equations yields \(n^2+n^2\ge 1+n\) \(\implies 2n^2-n\ge 1\)
LifeIsADangerousGame
  • LifeIsADangerousGame
Would testing each answer out work as well? I tried, but it didn't work out for me. Memorizing isn't my strong point, so I'm trying to figure out other methods.
Nnesha
  • Nnesha
i would do that.^^^^ :P

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Nnesha
  • Nnesha
i'll pick a number for n let n=-6 \[2(-6)^3+(-6)=2(-216)-6=-438\] so \[\ \cancel{E}\] \[(-6)^3 +(-6) = -216-6 =-222\] D isn't correct \[\ \cancel{D}\] \[(-6)^2+(-6)^3 = 36-216=-180\] \[\ \cancel{C}\] now there are 2 possible options hmmm\[\rm 2(-6)^2-(-6) ~and~(-6)^2-6\]
LifeIsADangerousGame
  • LifeIsADangerousGame
they both end up positive?
Nnesha
  • Nnesha
yeah...
LifeIsADangerousGame
  • LifeIsADangerousGame
so how do I know which one is correct?
Nnesha
  • Nnesha
\[\rm 2(-6)^2-(-6) ~and~(-6)^2-6\] \[2(36)\color{reD}{+}6 ~~~~~~~~~~~~~~~~~~~ 36\color{reD}{-}6\] hmmm i guess ^^addition ^subtraction different signs hmm LOL sometimes i use my own method *sigh*
Nnesha
  • Nnesha
anyway i'll work on this later i'm sleepy rn....
LifeIsADangerousGame
  • LifeIsADangerousGame
oh okay, thanks for your help!
Nnesha
  • Nnesha
np :)

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