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anonymous

  • one year ago

The number of pets owned by eight classmates is shown below: 1, 3, 2, 2, 1, 3, 3, 1 Part A: What is the mean of the data? Show your work. (4 points) Part B: Use your answer from Part A to calculate the mean absolute deviation for the data. Show your work. (6 points)

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  1. anonymous
    • one year ago
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    I already finished part A

  2. anonymous
    • one year ago
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    mean absolute deviation: https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-data-statistics/cc-6-mad/v/mean-absolute-deviation

  3. anonymous
    • one year ago
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    @Michele_Laino @geny55 @welshfella @LegendarySadist

  4. anonymous
    • one year ago
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    i got 2 for the absolute deviation is that correct please help?

  5. anonymous
    • one year ago
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    @skullpatrol @ali2x2 @IrishBoy123

  6. anonymous
    • one year ago
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    @Michele_Laino

  7. anonymous
    • one year ago
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    @Astrophysics

  8. Michele_Laino
    • one year ago
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    first step: the requested mean "m" is given by the subsequent computation: \[\Large m = \frac{{1 + 3 + 2 + 2 + 1 + 3 + 3 + 1}}{8} = ...\]

  9. anonymous
    • one year ago
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    16/8= 2

  10. Michele_Laino
    • one year ago
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    correct!

  11. Michele_Laino
    • one year ago
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    second step:

  12. Michele_Laino
    • one year ago
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    for each value v, you have to compute the difference: v-2 and take the result without the sign

  13. Michele_Laino
    • one year ago
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    namely, for example: 1-2= -1, so you take 1 3-2= 1, so you take 1 please continue

  14. anonymous
    • one year ago
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    1-2+3-2+2-2+2-2+1-2+3-2+3-2+1-2 so 1,1,0,0,1,1,1,1

  15. anonymous
    • one year ago
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    6

  16. anonymous
    • one year ago
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    6/8

  17. Michele_Laino
    • one year ago
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    the sum of the absolute deviations is 1+1+1+1+1+1=6 correct and the requested mean is: 6/8=...?

  18. Michele_Laino
    • one year ago
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    since we have 8 entries

  19. anonymous
    • one year ago
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    erm 1.2?

  20. Michele_Laino
    • one year ago
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    6/8=3/4=...?

  21. anonymous
    • one year ago
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    0.75

  22. Michele_Laino
    • one year ago
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    correct!

  23. anonymous
    • one year ago
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    Thank you for making it so much easier to understand (: @Michele_Laino I love your help

  24. Michele_Laino
    • one year ago
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    :)

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