anonymous
  • anonymous
The number of pets owned by eight classmates is shown below: 1, 3, 2, 2, 1, 3, 3, 1 Part A: What is the mean of the data? Show your work. (4 points) Part B: Use your answer from Part A to calculate the mean absolute deviation for the data. Show your work. (6 points)
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
I already finished part A
anonymous
  • anonymous
mean absolute deviation: https://www.khanacademy.org/math/cc-sixth-grade-math/cc-6th-data-statistics/cc-6-mad/v/mean-absolute-deviation

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anonymous
  • anonymous
i got 2 for the absolute deviation is that correct please help?
anonymous
  • anonymous
anonymous
  • anonymous
anonymous
  • anonymous
Michele_Laino
  • Michele_Laino
first step: the requested mean "m" is given by the subsequent computation: \[\Large m = \frac{{1 + 3 + 2 + 2 + 1 + 3 + 3 + 1}}{8} = ...\]
anonymous
  • anonymous
16/8= 2
Michele_Laino
  • Michele_Laino
correct!
Michele_Laino
  • Michele_Laino
second step:
Michele_Laino
  • Michele_Laino
for each value v, you have to compute the difference: v-2 and take the result without the sign
Michele_Laino
  • Michele_Laino
namely, for example: 1-2= -1, so you take 1 3-2= 1, so you take 1 please continue
anonymous
  • anonymous
1-2+3-2+2-2+2-2+1-2+3-2+3-2+1-2 so 1,1,0,0,1,1,1,1
anonymous
  • anonymous
6
anonymous
  • anonymous
6/8
Michele_Laino
  • Michele_Laino
the sum of the absolute deviations is 1+1+1+1+1+1=6 correct and the requested mean is: 6/8=...?
Michele_Laino
  • Michele_Laino
since we have 8 entries
anonymous
  • anonymous
erm 1.2?
Michele_Laino
  • Michele_Laino
6/8=3/4=...?
anonymous
  • anonymous
0.75
Michele_Laino
  • Michele_Laino
correct!
anonymous
  • anonymous
Thank you for making it so much easier to understand (: @Michele_Laino I love your help
Michele_Laino
  • Michele_Laino
:)

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