## anonymous one year ago The number of pets owned by eight classmates is shown below: 1, 3, 2, 2, 1, 3, 3, 1 Part A: What is the mean of the data? Show your work. (4 points) Part B: Use your answer from Part A to calculate the mean absolute deviation for the data. Show your work. (6 points)

1. anonymous

2. anonymous
3. anonymous

4. anonymous

5. anonymous

@skullpatrol @ali2x2 @IrishBoy123

6. anonymous

@Michele_Laino

7. anonymous

@Astrophysics

8. Michele_Laino

first step: the requested mean "m" is given by the subsequent computation: $\Large m = \frac{{1 + 3 + 2 + 2 + 1 + 3 + 3 + 1}}{8} = ...$

9. anonymous

16/8= 2

10. Michele_Laino

correct!

11. Michele_Laino

second step:

12. Michele_Laino

for each value v, you have to compute the difference: v-2 and take the result without the sign

13. Michele_Laino

namely, for example: 1-2= -1, so you take 1 3-2= 1, so you take 1 please continue

14. anonymous

1-2+3-2+2-2+2-2+1-2+3-2+3-2+1-2 so 1,1,0,0,1,1,1,1

15. anonymous

6

16. anonymous

6/8

17. Michele_Laino

the sum of the absolute deviations is 1+1+1+1+1+1=6 correct and the requested mean is: 6/8=...?

18. Michele_Laino

since we have 8 entries

19. anonymous

erm 1.2?

20. Michele_Laino

6/8=3/4=...?

21. anonymous

0.75

22. Michele_Laino

correct!

23. anonymous

Thank you for making it so much easier to understand (: @Michele_Laino I love your help

24. Michele_Laino

:)