anonymous
  • anonymous
Find the x value for point L such that JL and KL form a 3:1 ratio. A. 5.25 B. 2.33 C. 2.25 D. 4.33
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
1 Attachment
mathstudent55
  • mathstudent55
|dw:1439400000835:dw|
mathstudent55
  • mathstudent55
We place L on the segment, between J and K, in a way that JL = 3KL Ok so far?

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anonymous
  • anonymous
yes, perfect.
mathstudent55
  • mathstudent55
Now we need to find the x-coordinate of point L.
mathstudent55
  • mathstudent55
Here is our original graph again. |dw:1439400224309:dw|
mathstudent55
  • mathstudent55
Since point L creates a ratio of 3:1 for JL to KL, and 3 + 1 = 4, then point L is 1/4 of the way from K to J. Ok with this?
anonymous
  • anonymous
Ok!
mathstudent55
  • mathstudent55
The x-coordinate of point L is the same as the x-coordinate of the point below it on a horizontal line going from K to the x-coordinate of J. See figure below. |dw:1439400776719:dw|
mathstudent55
  • mathstudent55
Just like KL is 1/4 of KJ, so KL' is also 1/4 of KJ'.
mathstudent55
  • mathstudent55
|dw:1439400914014:dw|
mathstudent55
  • mathstudent55
We need to find the x-coordinate of point L'. The x-coordinate of point L is the same.
mathstudent55
  • mathstudent55
|dw:1439400979255:dw|
mathstudent55
  • mathstudent55
|dw:1439401009408:dw|
mathstudent55
  • mathstudent55
Along the horizontal line J'K, it's easy to see that the distance from J' to K is 7. Also, we know that from J to L it's 3/4 of the way from J to K. So from J' to L' it is 3/4 of the distance of J' to K. Since the distance from J' to K is 7, the distance from J' to L' is 3/4 * 7 = 5.25
anonymous
  • anonymous
thank you so much! you helped me a lot!
mathstudent55
  • mathstudent55
|dw:1439401248977:dw|
mathstudent55
  • mathstudent55
Finally, we add 5.25 to the x-coordinate of J' to get: 5.25 + -3 = 2.25
mathstudent55
  • mathstudent55
You're welcome.
anonymous
  • anonymous
can you help me with another one please?
mathstudent55
  • mathstudent55
Sure
mathstudent55
  • mathstudent55
pls start a new post
anonymous
  • anonymous
okay i will

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