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anonymous
 one year ago
sin[tan^1(8)]
anonymous
 one year ago
sin[tan^1(8)]

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Is tan^1(8) the arctan of 8 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Suppose you let \(x=\tan^{1}(8)\). This would mean that \(\tan x=8\). Keep in mind that \(\tan x\) is defined for \(\left(\dfrac{(2n+1)\pi}{2},\dfrac{(2n+3)\pi}{2}\right)\) for integers \(n\). Its inverse is typically defined by restricting the domain of \(\tan x\) to \(\left(\dfrac{\pi}{2},\dfrac{\pi}{2}\right)\) (i.e. the first and fourth quadrants of the unit circle). In terms of the quadrants, \(\tan x\) is negative for values of \(x\) within the second and fourth quadrants. Draw up a reference triangle with angle \(x\) such that \(\tan x=8=\dfrac{8}{1}\): dw:1439434906616:dw If you can find the missing side, you can determine \(\sin x=\sin\left(\tan^{1}(8)\right)\).
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