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HELP HELP HELP HELP HELP HELP HELP HELP HELP HELP HELP

Mathematics
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wait i'm calculating
but your height is given its 20
height is 20 cm
can i have an explanation
in a prism the side in your fig which is 20cm is always the hieght of the prism
yeah but what are the measurements
@madhu.mukherjee.946
dear its already mentioned in you fig its 20 cm
okay
i need it explained more
Help arrived
thanks so much......this needs an explanation
Ok this is a cake for me thanks for giving me the opportunity to eat it
Part A In finding the height of the box I first first consider the volume 2400 cm^2 with the means by which a triangle is calculated. In this case base*height*1/2. In this case that triangle is 3 dimensional. Therefore I consider the base which is comprised of 20cm*16cm=320cm^3 Now that we know the base, I use the formula base*height*1/2 to account for the height which is missing in this 3 dimensional figure. 320cm^2*x*0.5=2400cm^3 Now I isolate X 160cm^2(x)=2400cm^3 x=2400cm^3/160cm^2=15cm Therefore height of the triangle is 15 cm.
Now that height of the triangle is known, approximate amount of cardboard required to construct this 3 dimensional figure is calculated as follows. For base 16cm*20cm=320cm^2 For rectangles constituting sides 2(20cm*17cm)=680cm^2 For the triangles 2(16cm*15cm*0.5)=240cm^2 Now that areas for all sides of the 3D figures are known, they are to be added. 320cm^2+680cm^2+240cm^2=1240cm^2 Therefore 1240cm^2 worth of cardboard materials are required to construct the figure above.
@bubbleslove1234 lol you love me nowXD
Do you mind participating in a survey for my physical education assignment?
now???
Yup you can just find it in the forum
okay post it
Hey bubbles
can you help me with like two more problems
I love U.S.

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