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whats your question???
wait i'm calculating
but your height is given its 20
height is 20 cm
can i have an explanation
in a prism the side in your fig which is 20cm is always the hieght of the prism
yeah but what are the measurements
dear its already mentioned in you fig its 20 cm
i need it explained more
thanks so much......this needs an explanation
Ok this is a cake for me thanks for giving me the opportunity to eat it
Part A In finding the height of the box I first first consider the volume 2400 cm^2 with the means by which a triangle is calculated. In this case base*height*1/2. In this case that triangle is 3 dimensional. Therefore I consider the base which is comprised of 20cm*16cm=320cm^3 Now that we know the base, I use the formula base*height*1/2 to account for the height which is missing in this 3 dimensional figure. 320cm^2*x*0.5=2400cm^3 Now I isolate X 160cm^2(x)=2400cm^3 x=2400cm^3/160cm^2=15cm Therefore height of the triangle is 15 cm.
Now that height of the triangle is known, approximate amount of cardboard required to construct this 3 dimensional figure is calculated as follows. For base 16cm*20cm=320cm^2 For rectangles constituting sides 2(20cm*17cm)=680cm^2 For the triangles 2(16cm*15cm*0.5)=240cm^2 Now that areas for all sides of the 3D figures are known, they are to be added. 320cm^2+680cm^2+240cm^2=1240cm^2 Therefore 1240cm^2 worth of cardboard materials are required to construct the figure above.
@bubbleslove1234 lol you love me nowXD
Do you mind participating in a survey for my physical education assignment?
Yup you can just find it in the forum
okay post it
can you help me with like two more problems
I love U.S.