HELP HELP HELP HELP HELP HELP HELP HELP HELP HELP HELP

- anonymous

HELP HELP HELP HELP HELP HELP HELP HELP HELP HELP HELP

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- madhu.mukherjee.946

whats your question???

- anonymous

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@fratdog123

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- anonymous

@ganeshie8

- anonymous

@Haseeb96

- madhu.mukherjee.946

wait i'm calculating

- madhu.mukherjee.946

but your height is given its 20

- madhu.mukherjee.946

height is 20 cm

- anonymous

can i have an explanation

- anonymous

@ali2x2

- madhu.mukherjee.946

in a prism the side in your fig which is 20cm is always the hieght of the prism

- anonymous

yeah but what are the measurements

- anonymous

@madhu.mukherjee.946

- anonymous

@imqwerty

- madhu.mukherjee.946

dear its already mentioned in you fig its 20 cm

- anonymous

okay

- anonymous

i need it explained more

- anonymous

@imqwerty

- anonymous

@vera_ewing

- anonymous

@nincompoop

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@LunyMoony

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@imqwerty

- anonymous

@Robert136

- anonymous

Help arrived

- anonymous

thanks so much......this needs an explanation

- anonymous

Ok this is a cake for me thanks for giving me the opportunity to eat it

- anonymous

Part A
In finding the height of the box I first first consider the volume 2400 cm^2 with the means by which a triangle is calculated. In this case base*height*1/2.
In this case that triangle is 3 dimensional. Therefore I consider the base which is comprised of 20cm*16cm=320cm^3
Now that we know the base, I use the formula base*height*1/2 to account for the height which is missing in this 3 dimensional figure.
320cm^2*x*0.5=2400cm^3 Now I isolate X
160cm^2(x)=2400cm^3
x=2400cm^3/160cm^2=15cm
Therefore height of the triangle is 15 cm.

- anonymous

Now that height of the triangle is known, approximate amount of cardboard required to construct this 3 dimensional figure is calculated as follows.
For base
16cm*20cm=320cm^2
For rectangles constituting sides
2(20cm*17cm)=680cm^2
For the triangles
2(16cm*15cm*0.5)=240cm^2
Now that areas for all sides of the 3D figures are known, they are to be added.
320cm^2+680cm^2+240cm^2=1240cm^2
Therefore 1240cm^2 worth of cardboard materials are required to construct the figure above.

- anonymous

@bubbleslove1234 lol you love me nowXD

- anonymous

Do you mind participating in a survey for my physical education assignment?

- anonymous

now???

- anonymous

Yup you can just find it in the forum

- anonymous

okay post it

- anonymous

@Robert136

- anonymous

Hey bubbles

- anonymous

can you help me with like two more problems

- anonymous

@isaac4321

- anonymous

I love U.S.

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