The figure below shows a triangle with vertices A and B on a circle and vertex C outside it. Side AC is tangent to the circle. Side BC is a secant intersecting the circle at point X: The figure shows a circle with points A and B on it and point C outside it. Side BC of triangle ABC intersects the circle at point X. A tangent to the circle at point A is drawn from point C. Arc AB measures 100 degrees and angle CBA measures 42 degrees What is the measure of angle ACB?
What is the measure of angle ACB? 29° 8° 16° 21°
can u help anybody plz ill give medal
use the inscribed angle theorem to get AX = 2*(angle CBA) AX = 2*42 AX = 84 degrees
now use the formula angle ACB = (1/2)*(arc AB - arc AX) angle ACB = (1/2)*(100 - 84) angle ACB = ?
angle ACB = (1/2)*(arc AB - arc AX) angle ACB = (1/2)*(100 - 84) angle ACB = (1/2)*16 angle ACB = ? what is 16 times 1/2?
is it 8
thank u and u save m life
and tbh ur cute
the answer is 8