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\[\frac{ x+a }{ ax }=\frac{ b }{ x }\]

a=2 and b=3

what up

can i get a picture

ther isnt a picture its just the equation.......

alright so which part u need elp with 1 or 2

help

both...

\[\frac{ x+2 }{ 2x }=\frac{ 3 }{ x }\]

alright so do you want to find the variable x

is it 4?

yes nice job

it was 3/4

wat was 3/4?

the answer it was 3 over 4

how?....... i got 4.....

2+x =3 and 2x =4

call my name when you need help

wait how did u get that???

what up

adding 1 up top and multiplying 2 at the bottem

which is \[x+2=6\]

now your confusing me

and then u subtract 2 on both sides and get 4
\[x=4\]

yes

so thats the first part right?

yes

ok wat about the second part???

that is how you identify it

i didnt get that @Napolions

ya that page isnt opening...... @Napolions

go to google and type in extraneous solutions and it is under the one that say hot math

cross multiplication??

think so

im totally confused rn.........

what up

wat do i doo???>.........

x_x

i made a mistake in my previous problem....i did x*x is 2x butits x^2

ok so make the x 1

it was
x+22x=3x
3(2x)=x(x+2)
6x=x^2+2x
\[x^2+2x-\left(6x\right)=6x-\left(6x\right)\]

\[x^2-4x=0\]

are u checking to see if you are right do you need my help

can u check it once??

ok

\[x=4,\:x=0\]
right...?
and x=0 is the extraneous

correct

oh ok thxxxx.......

Medal plzzz

u know i did most of the question ^.^

lol but watev thx..........

yeah but i helped though but yeah you did most

lol