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anonymous
 one year ago
........
anonymous
 one year ago
........

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ x+a }{ ax }=\frac{ b }{ x }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ther isnt a picture its just the equation.......

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alright so which part u need elp with 1 or 2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ x+2 }{ 2x }=\frac{ 3 }{ x }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0alright so do you want to find the variable x

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the answer it was 3 over 4

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how?....... i got 4.....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0call my name when you need help

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait how did u get that???

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0adding 1 up top and multiplying 2 at the bottem

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im confused......... so first u multiply both sides by 2x.......then it gets canceled...... leaving \[x+2=\frac{ 3 }{ x }2x\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0now your confusing me

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and then u subtract 2 on both sides and get 4 \[x=4\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so thats the first part right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ok wat about the second part???

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0An extraneous solution is a root of a transformed equation that is not a root of the original equation because it was excluded from the domain of the original equation.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that is how you identify it

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i didnt get that @Napolions

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this website should help u Extraneous Solutions  Hotmath hotmath.com/hotmath_help/topics/extraneoussolutions.htm

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i mean this one Extraneous Solutions  Hotmath hotmath.com/hotmath_help/topics/extraneoussolutions.htm

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ya that page isnt opening...... @Napolions

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0go to google and type in extraneous solutions and it is under the one that say hot math

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait i think i did it wrong........ \[\frac{ x+2 }{ 2x } =\frac{ 3 }{ x }\] \[ 3(2x)= x(x+2)\] \[6x=2x+2x\] \[6x=4x\] @Napolions

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0cross multiplication??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im totally confused rn.........

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wat do i doo???>.........

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how does this sound??? x(x+1) = 2x x^2 + x = 2x x^2 x = 0 x(x1)=0 x=0 or x=1 the x=0 is extraneous, because we are not allowed to divide by 0 (which is what happens in the original equation if x is 0)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i made a mistake in my previous problem....i did x*x is 2x butits x^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it was x+22x=3x 3(2x)=x(x+2) 6x=x^2+2x \[x^2+2x\left(6x\right)=6x\left(6x\right)\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0are u checking to see if you are right do you need my help

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[x=\frac{\left(4\right)+\sqrt{\left(4\right)^24\cdot \:0\cdot \:1}}{2\cdot \:1}=4\]and \[x=\frac{\left(4\right)\sqrt{\left(4\right)^24\cdot \:0\cdot \:1}}{2\cdot \:1}=0\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0can u check it once??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[x=4,\:x=0\] right...? and x=0 is the extraneous

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0u know i did most of the question ^.^

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0lol but watev thx..........

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yeah but i helped though but yeah you did most
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