- anonymous

The number of pets owned by eight classmates is shown below:
1, 3, 2, 2, 1, 3, 3, 1
Part A: What is the mean of the data? Show your work. (4 points)
Part B: Use your answer from Part A to calculate the mean absolute deviation for the data. Show your work. (6 points)

- katieb

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- anonymous

I just need help with b

- anonymous

I got 2 for the absolute deviation is that correct?

- anonymous

what up

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## More answers

- anonymous

it is 2

- anonymous

so you was correct

- anonymous

can you show me how you know?

- welshfella

what did you get for the mean?

- anonymous

first you add all of the numbers which was 16 and then divide by how many people there was which was 8 so 16 divided by 8 is 2

- welshfella

thats the mean 2

- anonymous

for the part a i got 2

- welshfella

to get the mean absolute deviation you add up the absolute differences of each value from the mean . Add these values then divide by 8

- anonymous

yes

- welshfella

1 2-1 = 1
3 3 -2 = 1
2 2 -2 = 0
2 2 - 2 = 0
and so on

- anonymous

i did this to find the absolute deviation 1-2+3-2+2-2+2-2+1-2+3-2+3-2+1-2

- anonymous

so all that above 8

- anonymous

sure

- anonymous

so 6/8

- anonymous

yes

- anonymous

|dw:1439408182902:dw|

- welshfella

Hmm to be honest i'm not sure I'll have to check

- anonymous

same im confused im going to go over it again and you tell me how you it so we can compare

- anonymous

*do

- welshfella

right - you take ABSOLUTE values so for instance
first values is 1: 1 - 2 = -1 The absolute value of -1 is 1.
so there are no negatives

- welshfella

so 6/8 is not correct

- anonymous

alright

- anonymous

i was doing something else what

- welshfella

oh hold on it does work out to 6/8
it is 1+ 1 +0+ 0 + 1+ 1+1 + 1 = 6
so 6/8 or 3/4

- anonymous

Yeah

- anonymous

i see

- anonymous

ok

- welshfella

what you wrote
1-2+3-2+2-2+2-2+1-2+3-2+3-2+1-2 = 0

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