anonymous one year ago Given the following functions f(x) and g(x), solve f[g(7)] and select the correct answer below: f(x) = 4x + 21 g(x) = 2x + 2 16 49 85 784

1. anonymous

@campbell_st

2. anonymous

@e.mccormick @Elsa213

3. anonymous

@ali2x2 @heretohelpalways

4. anonymous

@ganeshie8 @thomaster

5. triciaal

work "inside out"

6. triciaal

find g(7) and use this value for x in f(x)

7. anonymous

okay.

8. triciaal

note that you will get the same result if you substitute the expression first then do the number last

9. anonymous

x=7g-2 -------- 2

10. anonymous

@triciaal

11. triciaal

no

12. triciaal

|dw:1439410483025:dw|

13. anonymous

g(7)=16

14. triciaal

|dw:1439410539696:dw|

15. anonymous

85?

16. anonymous

c?

17. triciaal

no question mark! yes good job.

18. anonymous

Can you also help with this: Given the following functions f(x) and g(x), solve (f + g)(5) and select the correct answer below: f(x) = 8x − 13 g(x) = x − 9 23 27 31 40

19. triciaal

|dw:1439410763924:dw|

20. triciaal

you can do the substitution first it's ok

21. anonymous

okay so 8*5 − 13+5-9 40-13+5-9 27+-4 23?

22. anonymous

A?

23. triciaal

yes

24. anonymous

one more... Given the functions f(x) = 7x + 13 and g(x) = x + 2, which of the following functions represents f[g(x)] correctly? f[g(x)] = 7x + 15 f[g(x)] = 7x + 27 f[g(x)] = 7x^2 + 15 f[g(x)] = 7x^2 + 27

25. anonymous

is it A?

26. triciaal

no

27. anonymous

C? I know you are adding 15, so

28. triciaal

g(x) is your x in f(x)

29. triciaal

|dw:1439411160771:dw|

30. triciaal

to simplify you expand the parenthesis and group like terms

31. anonymous

7*x+15

32. triciaal

NO

33. triciaal

read my directions click on the pencil to the right of the box and continue

34. anonymous

|dw:1439411604907:dw|

35. anonymous

@triciaal helloo?

36. triciaal

|dw:1439411682435:dw|

37. anonymous

so b

38. triciaal

when you distribute you multiply each term inside the parenthesis by what is outside

39. triciaal

yes

40. anonymous

thanks!

41. triciaal

you are welcome