## kearsten one year ago fan and medal include steps plz 0=8x^2 number of real number solutions

1. campbell_st

the only solution is x = 0

2. kearsten

how did you get that?

3. campbell_st

well what happnens if you replace x with 0 the equation is $8 \times 0^2$ and multiplying anything by 0 is 0 the other parts.... 8 can't be 0..... and the answer when squaring something is dependant on what you are squaring...

4. kearsten

ok thnx

5. kearsten

but that not what i needed

6. campbell_st

what do you need..?

7. campbell_st

0 is a real number

8. kearsten

i needed the number of solutions

9. campbell_st

1 solution... x= 0

10. campbell_st

well in actual fact there are 2 solutions.... both zero since its a degree 2 polynomial the degree or power of the leading term determines the number of solutions... the can be real or imaginary in your question they are both real