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anonymous
 one year ago
Adding rational expressions. I keep getting these wrong.
x/x^2+6x+9 + 7/x^2+8x+15
anonymous
 one year ago
Adding rational expressions. I keep getting these wrong. x/x^2+6x+9 + 7/x^2+8x+15

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\frac{ x }{ x^2+6x+7 } +\frac{ 7 }{ x^2+8x+15 }\] like this right ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0that was dauntingly fast !

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x^2+6x+9 on the first one

anonymous
 one year ago
Best ResponseYou've already chosen the best response.05(y+3)(y−1)/(y−3)2(y+1) my answer but I can't risk getting it wrong again.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I've been doing something wrong with factoring on these. it's the correct answer but i'm assuming they want the full answer, not factored. but I have no clue

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2haha alright try to factor quadratic equations apply the AC (headphone method) find two number when you multiply them you should get product of AC and when you add or subtract them you should get middle term Ax^2+Bx+C=0 a=leading coefficient b=middle term c=constant ter

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2so so what are the factors of x^2+6x+9 ??

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2so so what are the factors of x^2+8x+15??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have several of these to answer. will you help me with a few of them? I'm suppose to get 8 out of 10 correct and I was suppose to have all of this finished 22 minutes ago and I don't know if I submit this after i'm finish if it will even count. so i'm kinda panicked. haha I've done this test more than 10 times in the past week and still haven't figured out what i was doing wrong. decided to pay for owlbucks and have someone help me considering the deadline has already passed.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2do you know how to find factors quadratic equations ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2alright here is the easy method AC method (aka headphone method ) where you have to find two numbers when you multiply them you should get product of AC and when you add or subtract them you should get middle term dw:1439411259059:dw a= leading coefficient which is one b=middle term = 8 c=constant term = 15 so find two number when you multiply them you should get 15 but when you add or subtract them you should get 8

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I solved it with factoring and it was correct.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\(\color{blue}{\text{Originally Posted by}}\) @21pmakesmehappy 5(y+3)(y−1)/(y−3)2(y+1) my answer but I can't risk getting it wrong again. \(\color{blue}{\text{End of Quote}}\) is it like this ? \[\huge\rm \frac{ 5(x+3)(x1) }{ (x3)^2(x+1) }\] variable is x not y

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I redid it and got something different

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I have another question now. Can we try this one?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2well answer for that one is incorrect we should try it again!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.02y/y^2 2y+1 + 8/y^2+1y2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got the previous question correct once i redid it.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2have you tried to solve the 2nd one ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yes. i'm getting 2(y^2+6y4)/(y1)^2(y+2)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0but I know it'll be wrong if I put it as my answer.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge\rm \frac{ 2y }{ y^22y+1 } +\frac{ 8 }{ y^2+y 2 }\] find factor of quadratic equation y^22y+1 = find two number when we multiply them should get 1 and when we add them we should get 2 so 1 times 1= 1 11 = 2 perfect (x1)(x1) are the factors of y^22y+1 equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i think i need to put in the unfactored answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0because anytime i put it in factored, it's wrong

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.21st) factor quadratic equation 2nd) find common denominator

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\(\color{blue}{\text{Originally Posted by}}\) @Nnesha \[\huge\rm \frac{ 2y }{ y^22y+1 } +\frac{ 8 }{ y^2+y 2 }\] find factor of quadratic equation y^22y+1 = find two number when we multiply them should get 1 and when we add them we should get 2 so 1 times 1= 1 11 = 2 perfect (x1)(x1) are the factors of y^22y+1 equation \(\color{blue}{\text{End of Quote}}\) correction: (y1)(y1)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\huge\rm \frac{ 2y }{ y^22y+1 } +\frac{ 8 }{ y^2+y 2 }\] \[\rm \frac{ 2y }{ \color{reD}{(y1)}(y1) } +\frac{ 8 }{ (y+2)\color{ReD}{(y1)} }\] (y+2) (y1) are factors of y^2+y2 now what is the common denominator ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have no clue what im doing

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2yep right \[\huge\rm \frac{ 2y(y+2) +8(y1)}{ (y1)^2(y+2) }\] multiply the first fraction with the bottom of 2nd fraction multiply the 2nd fraction with the bottom of first one and f you distribute parentheses by outside terms you will get \[\frac{ 2y^2+12y8 }{ (y1)^2(y+2) }\] which is same as ur answer

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0it says it was incorrect.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\[\rm \frac{ 2y^2+12y8 }{ (y1)^2(y+2) } \] =\[\frac{ 2(y^2+6y4) }{ (y1)^2(y+2)}\] take out the GCF(greatest common factor

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04x/x^2+2x+1 + 3/x^2+3x+2 is the new question

anonymous
 one year ago
Best ResponseYou've already chosen the best response.04x^2 +11x+3/(x+1)^2(x+2 is the answer im getting

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0and i did not. i submitted my answer before you said to take out the gcf so it was incorrect

anonymous
 one year ago
Best ResponseYou've already chosen the best response.01 is the gcf, right?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so do I take 2 out of my final answer?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2no.. GCF is greatest common factor 2 is common in 2y^2 +12y 8 \[\color{ReD}{2} \times 1 \] \[1 \times \color{Red}{2} \times 3 \times 6 \times 12\] factors of 12 \[1 \times \color{ReD}{2} \times 4 \times 8\] factors of 8 2 is common factor of all 3 terms so yes take out 2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2\(\color{blue}{\text{Originally Posted by}}\) @Nnesha no.. GCF is greatest common factor 2 is common in 2y^2 +12y 8 \[\color{ReD}{2} \times 1 \] \[1 \times \color{Red}{2} \times 3 \times 6 \times 12\] factors of 12 \[1 \times \color{ReD}{2} \times 4 \times 8\] factors of 8 2 is common factor of all 3 terms so yes take out 2 \(\color{blue}{\text{End of Quote}}\) this is for 2nd question!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i am completely lost

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2please type the number front of the new question

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2like 2nd ) question 3rd) question

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have no clue what question im on

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0never give up, take a breath get a drink

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thanks for your help, though. i appreciate it a lot.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2relax! you are doing a great job!

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2alright i didn't give u a GREAT explanation so yeah i'll tag other users

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2@Hero @triciaal @nincompoop <!!!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is the problem factoring ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the only reason I have these answers is because I've done them each seriously 10 times today. I know how to solve these problems. I don't need an explanation as to how to solve these problems. i want to know why we match answers and when i put it into the system, it's wrong. I've gotten help from several people over the past week and i can't figure out why my answers are wrong. I appreciate the help but there is honestly no point in attempting this anymore. I've taken this test so many times and the deadline was over an hour ago. I could get all 10 correct and submit it and have it not even count. Your explanation was great and I genuinely appreciate the help. The problem is i get to my final answer, i enter it, it's wrong. I assume it has something to do with the factoring. someone suggested that I give "the full answer" "unfactored" but i have not one clue what that means.

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2i would like to see the screenshot of *multiple choice or answer box what is the statement ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay. how can i enter a photo?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2Press PrntScr to take a screenshot and do you see to blue *attach file* button to attach file ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I don't see an attach file button

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2show your work so i can loook over and find out some mistakes that would be great

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0This is the last question and i've already gotten 3 wrong. i can go back and take the test after i finish (if im not locked out) so hold on.

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0do you still need help?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I got locked out. My account is no longer active.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0besides factoring the nominator i don't see anything wrong (i'm might be doing it wrong too lol) what exactly is wrong @Nnesha

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2okay like you said you already know how to solve so it's better to post the work then no one would waste your time

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2ik numerator isn't correct so that's mean answer is not correct

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0well the numerator is correct (again i might be wrong ) just not factored

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439414757668:dw

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2alright let's see \[ \frac{ 6a }{ a^2+2a+1 } +\frac{ 7 }{ a^2+3a+2 }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2ohhhhhh i see *facepalm* it's 2 not 7

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0so your denominator is wrong

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2was looking at the wrong question.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0im pretty sure LCD is (a+2)(a+1)^2

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2ye answer is correct i'm sorry pma i was lookin at the wrong question.so i apologize

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0how are you getting \[(a+1)(a+2)\] for LCD @trwatkins1 ?

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0when one is a factor of the other you do not include

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439415089426:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0oops so sorry I forgot the square when I factored

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0sorry yes the LCD = (a +1)^2*(a+2)

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.2don't factor out the GCF *find the sum* try to submit your answer

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439415305928:dw

triciaal
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439415500982:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is a horrible way of learning to factor
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