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kearsten

  • one year ago

fan and medal plz include steps number of real-number solutions 0=4x^2+9 i tried mathway but couldnt find the topic

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  1. kearsten
    • one year ago
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    @nincompoop

  2. nincompoop
    • one year ago
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    \(4x^2+9 = 0 \rightarrow 4x^2 + 9 \color{red}{-9} = 0 \color{red}{-9} \) \(4x^2 = -9 \) then \(\large \frac{4x^2}{\color{red}{4}} = \frac{-9}{\color{red}{4}} \rightarrow x^2 = \frac{-9}{4}\) solve for x by obtaining the square root of both sides it will give you the solutions

  3. anonymous
    • one year ago
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    That seems right

  4. kearsten
    • one year ago
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    i still dont get its confusing

  5. anonymous
    • one year ago
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    It seems that way but it's really not

  6. kearsten
    • one year ago
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    can you help me?

  7. kearsten
    • one year ago
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    @isaac4321

  8. anonymous
    • one year ago
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    He pretty much got it under control I'm terrible at explaining stuff

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spraguer (Moderator)
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