## kearsten one year ago fan and medal plz include steps number of real-number solutions 0=4x^2+9 i tried mathway but couldnt find the topic

1. kearsten

@nincompoop

2. nincompoop

$$4x^2+9 = 0 \rightarrow 4x^2 + 9 \color{red}{-9} = 0 \color{red}{-9}$$ $$4x^2 = -9$$ then $$\large \frac{4x^2}{\color{red}{4}} = \frac{-9}{\color{red}{4}} \rightarrow x^2 = \frac{-9}{4}$$ solve for x by obtaining the square root of both sides it will give you the solutions

3. anonymous

That seems right

4. kearsten

i still dont get its confusing

5. anonymous

It seems that way but it's really not

6. kearsten

can you help me?

7. kearsten

@isaac4321

8. anonymous

He pretty much got it under control I'm terrible at explaining stuff