anonymous
  • anonymous
Rational Numbers and Expressions! Which Property is the following 15 + (k + 4) = 15 + (4 + k) Is it a... Closure property of addition? Closure property of multiplication? Commutative property of addition? Commutative property of multiplication? Associative property of addition? Associative property of multiplication? Identity property of addition? Identity property of multiplication? Inverse property of addition? Inverse property of multiplication? or a Distributive property or is the statement false? (I need help. I have 12 questions and I'm having trouble)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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Mehek14
  • Mehek14
Associative property of addition
Mehek14
  • Mehek14
because it doesn't matter where you put the parenthesis
anonymous
  • anonymous
thanks! could you help me with some more?

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More answers

anonymous
  • anonymous
@Mehek14
Mehek14
  • Mehek14
yea sure
anonymous
  • anonymous
15 + (4 + k) = (15 + 4) +k
Mehek14
  • Mehek14
that's associative property of addition as well
anonymous
  • anonymous
Thanks! 15 - (4 - k) = (15 - 4) - k
Mehek14
  • Mehek14
choices?
anonymous
  • anonymous
it's the same choices
Mehek14
  • Mehek14
i don't see anything for subtraction
Mehek14
  • Mehek14
they're all addition or multiplication
anonymous
  • anonymous
Do you think it might be Distributive property?
Mehek14
  • Mehek14
distributive property = 5(6+3) = 30 + 15
Mehek14
  • Mehek14
so no
anonymous
  • anonymous
Okay I'll just mark it for reveiw. Could you still help me with the others?
Mehek14
  • Mehek14
yea
anonymous
  • anonymous
\[\left[ -6 * \left( -\frac{ 1 }{ 6 } \right) \right] n =1 * n\]
Mehek14
  • Mehek14
choices?
Mehek14
  • Mehek14
if it's true or false, it's true
anonymous
  • anonymous
I think it might be inverse property of multiplication
anonymous
  • anonymous
what do you think?
Mehek14
  • Mehek14
inverse property of multiplication = \(\dfrac{7}{4}*\dfrac{4}{7}=1\)
anonymous
  • anonymous
So no?
Mehek14
  • Mehek14
probably
Mehek14
  • Mehek14
for the ones ur not sure, make a separate post and other people will try to help
anonymous
  • anonymous
Okay. Thanks for your help!
Mehek14
  • Mehek14
yw :)

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