anonymous
  • anonymous
Carl conducted an experiment to determine if there is a difference in the mean body temperature between men and women. He found that the mean body temperature for a sample of 100 men was 91.1 with a population standard deviation of 0.52 and the mean body temperature for a sample of 100 women was 97.6 with a population standard deviation of 0.45. Assuming the population of body temperatures for men and women is normally distributed, calculate the 98% confidence interval and the margin of error for the mean body temperature for both men and women.
Mathematics
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions.

anonymous
  • anonymous
Carl conducted an experiment to determine if there is a difference in the mean body temperature between men and women. He found that the mean body temperature for a sample of 100 men was 91.1 with a population standard deviation of 0.52 and the mean body temperature for a sample of 100 women was 97.6 with a population standard deviation of 0.45. Assuming the population of body temperatures for men and women is normally distributed, calculate the 98% confidence interval and the margin of error for the mean body temperature for both men and women.
Mathematics
schrodinger
  • schrodinger
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your free account and access expert answers to this
and thousands of other questions

anonymous
  • anonymous
I understand that the z-score formula needs to be used I'm just not sure exactly how to use it
nincompoop
  • nincompoop
|dw:1439414198837:dw|
anonymous
  • anonymous
x is the 1.5?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

nincompoop
  • nincompoop
no I am just showing you graphically how the problem is interpreted in the graph for a normally distributed curve
anonymous
  • anonymous
Ohhh, okay
anonymous
  • anonymous
I know the formula is z = (x - 91.1)/(.52) but I don't know how to go from there
nincompoop
  • nincompoop
\(\large \bar x \pm Z \frac{\sigma }{\sqrt{n}}\)
anonymous
  • anonymous
Whs is x? The probability?
anonymous
  • anonymous
What*
nincompoop
  • nincompoop
:( x bar is your mean remember?
nincompoop
  • nincompoop
http://www.stat.yale.edu/Courses/1997-98/101/confint.htm
nincompoop
  • nincompoop
we based it off sample mean since we do not have the population mean \(\mu \)
nincompoop
  • nincompoop
now just solve your z
anonymous
  • anonymous
Z-score for a 98% confidence interval is 2.33 right?
nincompoop
  • nincompoop
I didn't solve it, how did you get that ?
nincompoop
  • nincompoop
common value?
anonymous
  • anonymous
In my notes, I copied down a list of the different scores. Yeah, a common value
nincompoop
  • nincompoop
oaky then use the rest of the formula to get the confidence interval and error
nincompoop
  • nincompoop
|dw:1439415558976:dw|
nincompoop
  • nincompoop
|dw:1439415585464:dw|
anonymous
  • anonymous
90.9784 91.22116
anonymous
  • anonymous
isn't .52/10 is .052
nincompoop
  • nincompoop
true haha
anonymous
  • anonymous
\[97.6\pm2.33\times\frac{ .45 }{ \sqrt{100} }\]
anonymous
  • anonymous
And that's for women?
anonymous
  • anonymous
97.49515 = 97.5 97.70485 = 97.7
nincompoop
  • nincompoop
correct
anonymous
  • anonymous
So those were the confidence intervals?
nincompoop
  • nincompoop
correct
anonymous
  • anonymous
So then what's the margin of error?
nincompoop
  • nincompoop
you use almost the same formula but without the sample mean
anonymous
  • anonymous
I'm sorry if I'm being difficult, I'm studying for my final and this is the only section I didn't understand
anonymous
  • anonymous
So the margin of error is .12116 for men and .10485 for women?
anonymous
  • anonymous
Thank you so much for your help, I think I actually get it now :))
nincompoop
  • nincompoop
btw, what book do you use for statistics?
anonymous
  • anonymous
I'm in Algebra 2 Honors, Statistics is just a couple chapters we cover
nincompoop
  • nincompoop
ah
nincompoop
  • nincompoop
if you want a book, which I think you are going to need let me know you will retake this in college again and you should even though you took AP or honors because it is a little more in-depth quite intense.
anonymous
  • anonymous
I'm taking Calc and AP Stats next year so if you have any suggestions for books that'd be great
anonymous
  • anonymous
Please let me know when you have it so I can delete it off of here :)
nincompoop
  • nincompoop
k
nincompoop
  • nincompoop
sent you a link
anonymous
  • anonymous
Thank you so much! :)
nincompoop
  • nincompoop
if for some reason you want to use the DVD or video lectures and have difficulty playing them, use MPlayerX program, you won't need to worry about codex or anything to use it and can play almost every video file format known to mankind.
anonymous
  • anonymous
I will probs only use the book, but thank you for everything :)
anonymous
  • anonymous
@nincompoop it says I need to rate you or you don't get your "rewards" and that there should be a bell moving around but there is no bell
nincompoop
  • nincompoop
There is no need to rate me, I am more concerned with you understanding the subject matter. Let us skip that portion for now and try again next time.

Looking for something else?

Not the answer you are looking for? Search for more explanations.