Fun tricky question. Alcohol hydrogens are more acidic than alkane hydrogens.
So why are bond dissociation energies of an O-H bond higher than a C-H bond?
Good luck and medal + fan to ya if you get it! :P Feel free to post any ideas you have, I'll post the answer by tomorrow if no one gets it.
Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
More acidic, I guess because acidity depends on the stability of the resulting ion. If the ion is more stable then it will probably be more willing to give up a hydrogen. The better the acid the more stable it's conjugate base will be. The alcohol would be more stable than say the carbanion formed from say ch4 if that were possible. There are a number of things that acidity depends on and if we rank them it's a good menemonic called ARIO atom, resonance, induction, orbitals, we consider the atom first the. Resonance and so on and so forth for ranking acidity.
ROH ----> RO-
ch4 ---> ch3-
Bond dissociation energy for OH vs CH
Generally if the O-H bond is more acidic it should imply that the bond is easier to break than a CH bond.
But based off of your question, this seems like the opposite. OH bond is harder to break. I think that it could be the electronegativity difference though it's probably not that simple.
Aha you've at least understood why this is tricky, there's something at play here. Actually the reason has to do with something very subtle here. There is a trick here being made, this comparison is actually illegitimate.