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anonymous

  • one year ago

for all real numbers A and B, if A @ B = a(a-b), then A @ (A@B) =

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  1. anonymous
    • one year ago
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    my answer say it wrong i put a^3-a^2b but it say wrong. can help me?

  2. anonymous
    • one year ago
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    a @ (a @ b) = a(a - (a @ b) ) = a(a - a(a-b))

  3. anonymous
    • one year ago
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    which equals -a^3 + a^2b + a^2

  4. anonymous
    • one year ago
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    why is a(a-(a-b)? why not a(a(a-b)) ??

  5. anonymous
    • one year ago
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    A = a B = (a-b) ?

  6. anonymous
    • one year ago
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    let c = a@b, then what does a@c equal according to the definition of @?

  7. anonymous
    • one year ago
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    a(a-b) ?

  8. anonymous
    • one year ago
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    a@c = a(a - c)

  9. anonymous
    • one year ago
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    ooh! ok salamat

  10. anonymous
    • one year ago
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    but c = a@b, so c = a(a-b). Substitute and you'll see

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