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anonymous
 one year ago
hi
anonymous
 one year ago
hi

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0what is your question about this quadratic equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0x(x4)=0 x=0 or x4=0 x=0 or x=4

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4find the GCF what is common in both terms ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i need help using the quadratic formula for this problem........

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4oaky should mention that *using the qudratic formula*

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4\[\huge\rm x=\frac{ b \pm \sqrt{b^24ac} }{ 2a }\] plugin a ,b c values \[\huge\rm Ax^2+Bx+C=0\] a=leading coefficient b= middle term c= constant term

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 4\sqrt{16  0} }{ 2}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0actually nvm listen to @Nnesha

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0damn i think i just gave her the answer ... sorry about that @Nnesha

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4\[\huge\rm \color{reD}{A}x^2+\color{blue}{B}x+\color{green}{C}=0\] \[\huge\rm \color{reD}{1}x^2\color{blue}{4}x=0\]a ,b ,c values are a= leading coefficient b=middle term c=constant term

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4so what is a , b and c in this equation 1x2 4x = 0 ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0this is wat i got so far,,, \[\frac{ (4±\sqrt{4^24*0*1}) }{ 2*1}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i know how to substitute and all..its the solving part......... @Nnesha

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4put the parentheses (4)^2

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oops ok next.........

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.44^2 isn't same as (4)^2 and there is negative sign in the formula and b value is also negative \[\huge\rm \frac{\color{ReD}{} (4)±\sqrt{(4)^2(4*0*1)} }{ 2*1}\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ (−(4)±\sqrt{16−4∗0∗1}) }{ 2 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 4±\sqrt{1} }{ 2 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 4\pm1 }{ 2 }\]

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 4+1 }{ 2 }=\frac{ 5 }{ 2 }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4how did you get one under the square root ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0\[\frac{ 41 }{ 2 }=\frac{ 3 }{ 2 }\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4\(\color{blue}{\text{Originally Posted by}}\) @plzzhelpme \[\frac{ 4±\sqrt{1} }{ 2 }\] \(\color{blue}{\text{End of Quote}}\) here how did you get one ? :)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i subtracted 4 from 16 = 12 then 12*0*1=1

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0ohhh i did that part wrong.......

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4ye ^^ try again \[\sqrt{16(4 \times 0 \times 1)}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4when ou multiply a number by 0 what will you get ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.44 times 0 ? x times 0 = ?? chocolates times 0 ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4yes so 4 times 0 times 1 = 0 \[\sqrt{16(4 \times 0 \times 1)}\] \[\sqrt{160}\]

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4\(\color{blue}{\text{Originally Posted by}}\) @plzzhelpme \[\frac{ 4±\sqrt{1} }{ 2 }\] \(\color{blue}{\text{End of Quote}}\) so it's \[x=\frac{ 4±\sqrt{16} }{ 2 }\] take square root of 16 and then solve!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@Nnesha how would u check the solution when we only have : x=4 ?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4plug it into the equation if both sides are equal then yes 4 is a solution of that equation and if both sides are not equal then nope 4 isn't a solution of that equation

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got this https://www.symbolab.com/solver/stepbystep/4%5E%7B2%7D4%5Cleft(4%5Cright)%3D0/?origin=enterkey @Nnesha

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4let 's use our own pretty hands 4^324(4) = 0 1616=0 both sides are equal r?

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4ohh my bad *backspace* button isn't working only on this page so yea

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4\(\color{blue}{\text{Originally Posted by}}\) @Nnesha let 's use our own pretty hands 4^324(4) = 0 1616=0 both sides are equal r? \(\color{blue}{\text{End of Quote}}\) correction 4^2 4(4)=0

Nnesha
 one year ago
Best ResponseYou've already chosen the best response.4wiill give you 1616=0 (1616) =0 so 0=0 both sides are equal so yes 4 is a solution

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0yayyy thx soo much........
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