anonymous
  • anonymous
Medal and Fan Im not very good at algebra Arianna kicks a soccer ball off the ground and into the air with an initial velocity of 42 feet per second. Assume the starting height of the ball is 0 feet. Approximately what maximum height does the soccer ball reach? 1.3 ft 2.6 ft 26.0 ft 27.6 ft
Mathematics
jamiebookeater
  • jamiebookeater
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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anonymous
  • anonymous
anonymous
  • anonymous
Using the same H(t) formula from the last one H(t) = -16t² + vt + s, what's v and what's s?
anonymous
  • anonymous
v is 42 s is 0?

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anonymous
  • anonymous
yep, so we have H(t) = -16t² + 42t so now we just need to find the vertex. For a quadratic function in the form \[y=ax^2+bx+c\] the vertex is \[\left( \frac{ -b }{ 2a },f \left( \frac{ -b }{ 2a } \right) \right)\] We have a = -16, b = 42, and c = 0 So for the time, find \[t=\frac{ -42 }{ 2*-16 }\] Then plug it into our function to get the max height
anonymous
  • anonymous
ok so it would be h(t)=-16t^2 + 42t and substitute 1.31 for t?
anonymous
  • anonymous
yes
anonymous
  • anonymous
and the answer becomes D correct?
anonymous
  • anonymous
yes

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