Looking for something else?

Not the answer you are looking for? Search for more explanations.

## More answers

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

Let f(x) = 4x2 + x + 1 and g(x) = x2 – 2. Find g(f(x)). Show each step of your work.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions.

Get your **free** account and access **expert** answers to this and **thousands** of other questions

- anonymous

Let f(x) = 4x2 + x + 1 and g(x) = x2 – 2. Find g(f(x)). Show each step of your work.

- chestercat

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this

and **thousands** of other questions

- anonymous

can someone help me out with this one?

- anonymous

@Hero hey are you busy right now? do you have time right now to help or should i ask later?

- anonymous

To find f(g(x)) you replace all the x's in f(x) with the expression from g(x).|dw:1439418816269:dw|

Looking for something else?

Not the answer you are looking for? Search for more explanations.

- anonymous

it's not f(g(x) though

- anonymous

it's g(f(x))

- anonymous

My issue with why I'm confused is when you put the f in the g, i got gx=(4x^2 + x +1)^2 but that doesnt seem right

- anonymous

you are right. I misread it. You just do it the other way around. Replace x in g(x) with 4x² + x + 1

- anonymous

What you have is right, you just need to keep the -2

- anonymous

\[g(f(x)) = (4x^2+x+1)^2-2\]

- anonymous

do you have to expand it?

- anonymous

ok do you do (4x^2 + x + 1) * (4x^2 + x + 1) or do you just apply the ^2 one time?

- anonymous

yea you gotta solve it i guess

- anonymous

yeah you have to do (4x^2 + x + 1) * (4x^2 + x + 1)

- anonymous

ok i did that and im so confused tbh like idk what to do

- anonymous

i know how to multiply everything but its just so much

- anonymous

yeah it's a lot to keep track of. I distribute everything in the 1st parentheses to everything in the 2nd and add them all up at the end.|dw:1439419351533:dw|

- anonymous

then combine with the -2

- anonymous

flutter ok i knew i was doing it right i just wasnt sure. anyway thank you so much man i really appreciate it

- anonymous

you're welcome

Looking for something else?

Not the answer you are looking for? Search for more explanations.