## anonymous one year ago If a factory continuously pumps pollutants into the air at the rate of the quotient of the square root of t and 15 tons per day, then the amount dumped after 3 days is

1. anonymous

$\frac{ \sqrt{t} }{ 15 }$

2. anonymous

@IrishBoy123 @triciaal

3. anonymous

u need me bro

4. anonymous

umm yeah

5. anonymous

wait was that a question or a statement ?

6. anonymous

it is 45 tons in three days

7. anonymous

sorry its 6.708203932

8. anonymous

Medal plzzzzzzzzzzzzzzzzzzzzzz

9. IrishBoy123

$$\large \frac{dP}{dt} = \frac{\sqrt{t}}{15}$$ $$\large P(3) = \frac{1}{15} \ \int_{t=0}^{3} \sqrt{t} \ dt = \frac{1}{15} | \frac{2}{3}.t^{3/2}|_{t=0}^{3} = \frac{2}{45}. \sqrt{27} =\frac{2 \sqrt{3}}{15} = 0.231$$

10. anonymous

what

11. anonymous

now im confused

12. IrishBoy123

@watchpencilpaper is this what you were expecting? did you have a method in mind for solving this?

13. anonymous

yes

14. anonymous

i

15. anonymous

did

16. anonymous

have

17. anonymous

a

18. anonymous

method

19. anonymous

no i had no method in mind and it appears you are right @IrishBoy123

20. IrishBoy123

@watchpencilpaper so how were you going to solve this -- without using calculus?!?!

21. IrishBoy123

22. anonymous

what do you mean, i intended to say i did not know how to solve it, obviously you need calculus

23. IrishBoy123

ok @Napolions please, is there a cooler way to do this? do share.

24. anonymous

naw but there was a website that helped me

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