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anonymous

  • one year ago

If a factory continuously pumps pollutants into the air at the rate of the quotient of the square root of t and 15 tons per day, then the amount dumped after 3 days is

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  1. anonymous
    • one year ago
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    \[\frac{ \sqrt{t} }{ 15 }\]

  2. anonymous
    • one year ago
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    @IrishBoy123 @triciaal

  3. anonymous
    • one year ago
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    u need me bro

  4. anonymous
    • one year ago
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    umm yeah

  5. anonymous
    • one year ago
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    wait was that a question or a statement ?

  6. anonymous
    • one year ago
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    it is 45 tons in three days

  7. anonymous
    • one year ago
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    sorry its 6.708203932

  8. anonymous
    • one year ago
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    Medal plzzzzzzzzzzzzzzzzzzzzzz

  9. IrishBoy123
    • one year ago
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    \(\large \frac{dP}{dt} = \frac{\sqrt{t}}{15} \) \(\large P(3) = \frac{1}{15} \ \int_{t=0}^{3} \sqrt{t} \ dt = \frac{1}{15} | \frac{2}{3}.t^{3/2}|_{t=0}^{3} = \frac{2}{45}. \sqrt{27} =\frac{2 \sqrt{3}}{15} = 0.231\)

  10. anonymous
    • one year ago
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    what

  11. anonymous
    • one year ago
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    now im confused

  12. IrishBoy123
    • one year ago
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    @watchpencilpaper is this what you were expecting? did you have a method in mind for solving this?

  13. anonymous
    • one year ago
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    yes

  14. anonymous
    • one year ago
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    i

  15. anonymous
    • one year ago
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    did

  16. anonymous
    • one year ago
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    have

  17. anonymous
    • one year ago
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    a

  18. anonymous
    • one year ago
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    method

  19. anonymous
    • one year ago
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    no i had no method in mind and it appears you are right @IrishBoy123

  20. IrishBoy123
    • one year ago
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    @watchpencilpaper so how were you going to solve this -- without using calculus?!?!

  21. IrishBoy123
    • one year ago
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    @Napolions your method please!! please share it.

  22. anonymous
    • one year ago
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    what do you mean, i intended to say i did not know how to solve it, obviously you need calculus

  23. IrishBoy123
    • one year ago
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    ok @Napolions please, is there a cooler way to do this? do share.

  24. anonymous
    • one year ago
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    naw but there was a website that helped me

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