anonymous
  • anonymous
If a factory continuously pumps pollutants into the air at the rate of the quotient of the square root of t and 15 tons per day, then the amount dumped after 3 days is
Mathematics
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
\[\frac{ \sqrt{t} }{ 15 }\]
anonymous
  • anonymous
@IrishBoy123 @triciaal
anonymous
  • anonymous
u need me bro

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anonymous
  • anonymous
umm yeah
anonymous
  • anonymous
wait was that a question or a statement ?
anonymous
  • anonymous
it is 45 tons in three days
anonymous
  • anonymous
sorry its 6.708203932
anonymous
  • anonymous
Medal plzzzzzzzzzzzzzzzzzzzzzz
IrishBoy123
  • IrishBoy123
\(\large \frac{dP}{dt} = \frac{\sqrt{t}}{15} \) \(\large P(3) = \frac{1}{15} \ \int_{t=0}^{3} \sqrt{t} \ dt = \frac{1}{15} | \frac{2}{3}.t^{3/2}|_{t=0}^{3} = \frac{2}{45}. \sqrt{27} =\frac{2 \sqrt{3}}{15} = 0.231\)
anonymous
  • anonymous
what
anonymous
  • anonymous
now im confused
IrishBoy123
  • IrishBoy123
@watchpencilpaper is this what you were expecting? did you have a method in mind for solving this?
anonymous
  • anonymous
yes
anonymous
  • anonymous
i
anonymous
  • anonymous
did
anonymous
  • anonymous
have
anonymous
  • anonymous
a
anonymous
  • anonymous
method
anonymous
  • anonymous
no i had no method in mind and it appears you are right @IrishBoy123
IrishBoy123
  • IrishBoy123
@watchpencilpaper so how were you going to solve this -- without using calculus?!?!
IrishBoy123
  • IrishBoy123
@Napolions your method please!! please share it.
anonymous
  • anonymous
what do you mean, i intended to say i did not know how to solve it, obviously you need calculus
IrishBoy123
  • IrishBoy123
ok @Napolions please, is there a cooler way to do this? do share.
anonymous
  • anonymous
naw but there was a website that helped me

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