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anonymous
 one year ago
List the first four terms of a geometric sequence with t1 = 4 and tn = 3tn1.
im lost...again
anonymous
 one year ago
List the first four terms of a geometric sequence with t1 = 4 and tn = 3tn1. im lost...again

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anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@ospreytriple @Mehek14

campbell_st
 one year ago
Best ResponseYou've already chosen the best response.0so for the 2nd term substitute n = 2 t2 = 3 x t1 so t2 = 3 x 4 t2 = 12 and then repeat the process for n =3 and n = 4 hope it helps

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0For \(t_2\), put 2 in for \(n\) in the given formula, i.e.\[t_2 = 3\times t_{21} = 3\times t_1\]and you know what \(t_1\) is.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i got 12, is there more i have to do?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Correct. Now you have \(t_1\) and \(t_2\). The question asks for the first four terms, so you need to repeat what you did above and calculate \(t_3\) and \(t_4\).

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so for t3 i do t3=12 x t31?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Not quite. The formula is\[t_n = 3 t_{n1}\]The 3 is a constant, it never changes. In fact, when you understand the pattern, you'll see that 3 is the common ratio.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0is t3=3t31 t3=3t2 t3=3(12) t3=36 like that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Excellent! Now, what's \(t_4\) ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0t4=3t41 3t3 3(36) 108 like that?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Congrats! Problem finished.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0thank you!. im glade you someone who shows me then just tells me the anwser

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0I agree. You're welcome.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0just woundering, but are you good with ellipses and hyperbola?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay i have another question...ill start another one
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