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anonymous

  • one year ago

WILL MEDAL AND FAN! Create your own factorable polynomial with a GCF. Rewrite that polynomial in two other equivalent forms. Explain how each form was created.

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  1. anonymous
    • one year ago
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    @peachpi

  2. anonymous
    • one year ago
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    @triciaal

  3. anonymous
    • one year ago
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    @Nnesha

  4. anonymous
    • one year ago
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    I'd start in factored form and then multiply to get the polynomial. It seems like you can write 2 different binomials and then use a monomial to be the GCF.

  5. anonymous
    • one year ago
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    can you help me with that please!

  6. anonymous
    • one year ago
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    I can help you put them together once you make them up. They can pretty much be whatever you want. Do you know what binomials and monomials are?

  7. anonymous
    • one year ago
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    Yes i do :]. Binomials is a polynomial with "2" terms. Minomials are polynomials that only have "1" term.

  8. anonymous
    • one year ago
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    that's right. this question is literally asking you to make up 2 binomials and 1 monomial and then multiply them

  9. anonymous
    • one year ago
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    OH. Can i make one real quick and can you check to make sure i am correct?

  10. anonymous
    • one year ago
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    ok

  11. anonymous
    • one year ago
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    Ok give me 1 min.

  12. anonymous
    • one year ago
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    (2a^3)*(2a+3a)?

  13. anonymous
    • one year ago
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    OH I forgot 1

  14. anonymous
    • one year ago
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    (2a^2) * (2a^3+3a)*(4a+3a^2)?

  15. anonymous
    • one year ago
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    That works perfectly.

  16. anonymous
    • one year ago
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    But it says: "Rewrite that polynomial in two other equivalent forms. Explain how each form was created."

  17. anonymous
    • one year ago
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    so that can be one of your forms

  18. anonymous
    • one year ago
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    Another form comes when you multiply everything together. Do you know FOIL?

  19. anonymous
    • one year ago
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    No sorry i don't.

  20. anonymous
    • one year ago
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    It stands for First, Outer, Inner, Last and it helps with distribution for binomials. You multiply the terms together, then add them up. We're going to use it to multiply the 2 binomials. |dw:1439422276593:dw|

  21. anonymous
    • one year ago
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    Or is descending order (just because it's neater), the binomial multiply to \[6a^5+8a^4+9a^3+12a^2\]

  22. anonymous
    • one year ago
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    does that make sense?

  23. anonymous
    • one year ago
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    Yes! Explain how each form was created.? What would i say for this part?

  24. anonymous
    • one year ago
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    you made up the first one and we're still multiplying to get the second one.

  25. anonymous
    • one year ago
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    Now you just have to distribute the monomial \[2a^2(6a^5+8a^4+9a^3+12a^2)\]

  26. anonymous
    • one year ago
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    12a^7+16a^6+18a^5+24a^4?

  27. anonymous
    • one year ago
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    yes, so that's your 2nd form

  28. anonymous
    • one year ago
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    For the 3rd one, factor out the GCF of all 4 terms

  29. anonymous
    • one year ago
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    do you know what the GCF is for this polynomial?

  30. anonymous
    • one year ago
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    I don't know what you mean?

  31. anonymous
    • one year ago
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    @Vocaloid

  32. anonymous
    • one year ago
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    @peachpi P[lease come back and help!

  33. anonymous
    • one year ago
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    Is the GCF : ? ( Its in the attachment.)

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  34. anonymous
    • one year ago
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    It said create a polynomial with a GCF. The GCF is the lowest power of the variable multiplied by the largest number that goes into all coefficients. What's the biggest number the divides evenly into 12, 16, 18, and 24? What is the smallest power of a?

  35. anonymous
    • one year ago
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    The thing you posted is the polynomial in expanded form. We're looking for the greatest common factor of all those terms

  36. anonymous
    • one year ago
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    The answer would be 4???

  37. anonymous
    • one year ago
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    4 doesn't go into 18

  38. anonymous
    • one year ago
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    6?

  39. anonymous
    • one year ago
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    2

  40. anonymous
    • one year ago
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    So thats my answer for GCF?

  41. anonymous
    • one year ago
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    so the GCF is \(2a^4\). You need to divide all the terms in \(12a^7+16a^6+18a^5+24a^4\) by \(2a^4\) to factor

  42. anonymous
    • one year ago
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    that will give you the last form you need

  43. anonymous
    • one year ago
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    Can you help me i am confused. Plus i wanna make sure i am right.

  44. anonymous
    • one year ago
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    |dw:1439425459781:dw|

  45. anonymous
    • one year ago
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    |dw:1439425542843:dw|

  46. anonymous
    • one year ago
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    |dw:1439425661554:dw|

  47. anonymous
    • one year ago
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    so now add them all up and write the GCF on the outside \[2a^4(6a^3+8a^2+9a+12)\]

  48. anonymous
    • one year ago
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    that's the factored form

  49. anonymous
    • one year ago
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    12a7+16a6+18a5+24a4

  50. anonymous
    • one year ago
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    12a^7+16a^6+18a^5+24a^4

  51. anonymous
    • one year ago
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    ^that's what we had originally. We factored it to get a third form. Have you done factoring yet?

  52. anonymous
    • one year ago
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    I am sorry i am confused what is the GCF in this problem?

  53. anonymous
    • one year ago
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    The answer.

  54. anonymous
    • one year ago
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    2x^4

  55. anonymous
    • one year ago
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    ok

  56. anonymous
    • one year ago
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    Is that all i need in This problem?

  57. anonymous
    • one year ago
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    yes

  58. anonymous
    • one year ago
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    Ok thank you!

  59. anonymous
    • one year ago
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    you're welcome.

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