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anonymous
 one year ago
Hi, i ask this the other day and if someone can solve it with answer and explains, will fan and medal: When a beam makes an angle of 40 degrees with the ground, the top of the beam is 40 feet above the ground. There a telephone wires near by and the worker worried that the beam may hit the wires. When the beam makes a angle of 60 degrees with the ground, the wires are 2 feet above the beam. Will the beam hit the ground if the crew continues to raise it?
anonymous
 one year ago
Hi, i ask this the other day and if someone can solve it with answer and explains, will fan and medal: When a beam makes an angle of 40 degrees with the ground, the top of the beam is 40 feet above the ground. There a telephone wires near by and the worker worried that the beam may hit the wires. When the beam makes a angle of 60 degrees with the ground, the wires are 2 feet above the beam. Will the beam hit the ground if the crew continues to raise it?

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Nnesha
 one year ago
Best ResponseYou've already chosen the best response.0looks like physics q lel :P well i have to go wait for someone or i'll llook at 't later !

radar
 one year ago
Best ResponseYou've already chosen the best response.0dw:1439431270274:dw I believe the question should be does the pole hit the WIRE as they continue to raise it, it will hit the ground if they drop it.!

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@radar: i'm sorry, it suppose to be if it hit the wires or not.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3dw:1439437785859:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3Let's look at the beam at 40 deg to the ground.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3dw:1439437990141:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3\(\sin 40^o = \dfrac{40~ft}{L}\) \(L = \dfrac{40~ft}{\sin 40^o} \approx 62.23 ~ ft\)

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3Now we know the length of the beam. Now we look at the situation when the beam is at 60 degrees from the ground.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3dw:1439438459934:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3Notice I just corrected the length of the beam. I just noticed my calculator was set to radians and the length of the beam was incorrect. The length of the beam is 62.23 ft. This number is correct now.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3Now we find h, the height of the beam when it is at a 60deg angle with the ground.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3\(\sin 60^o = \dfrac{h}{62.23~ft} \) \(h = (62.23~ft)\sin 60^o \approx 53.89~ft \)

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3Since the wires are 2 ft higher than the top of the beam when the beam is at 60 deg with the ground, the wires are at 55.89 ft above the ground.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3Since the beam is 62.23 ft long, and the wires are only 55.89 ft above ground, if the crew continues to raise the angle of the beam, the beam WILL HIT the wires.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3At what angle of the beam will it hit the wires? dw:1439438842464:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Beware the OS Code of Conduct!

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3\(\sin x = \dfrac{55.89}{62.23} \) \(\sin^{1} \dfrac{55.89}{62.23} = 63.91^o\) At 63.91 deg, the beam will hit the wires.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3@Leong Do you understand?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@mathstudent55 yes :) thank you :) I was just drawing it again and again but didn't think of the law of sines :)

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3I did not use the law of sines. This is simply the definition of the sine in a right triangle.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3dw:1439439303636:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3We used the sine ratio which is opp/hyp. dw:1439439409054:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3To find the length of the beam, we did this: dw:1439439471920:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3To find the heigth the beam reaches at 60 deg, we did this: dw:1439439571183:dw

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0wait, so like the beam will hit the wires at 60 something degree, because Sin^1(53.89 over62.23 =59.99

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3It equals 63.91 deg. Yes, when the beam is at 63.91 deg with the ground, the beam will hit the wires.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay, thanks. i bad at round numbers

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3No problem. You're welcome.

radar
 one year ago
Best ResponseYou've already chosen the best response.0You beat me to this, @mathstudent55 and did an excellent step by step job. I could not done any better or clear explanation. You certainly deserve the medal.

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.3@radar A good word from you means a lot to me. I really appreciate it. Also, thanks for the testimonial.

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0@mathstudent55 hey, so I got a mistake that the when th beam make angle of 40 degree then from the beam to the ground is 8ft, so the beam won't hit the wires since we know that the beam is 12,45 ( I had calculator again myself) and when it make angle of 60 then from the beam to the sruface is 10,78. by that, the beam WILL NOT hit the wires, so do I have to find anything else when I know that the beam will not hit the wires?

radar
 one year ago
Best ResponseYou've already chosen the best response.0Please post the problem again, providing correct info. The problem as presently posted, states that at 40 degrees elevation, the top of the beam is 40 ft. above the ground. How you got 12.45 ft. is not clear.
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