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anonymous

  • one year ago

Choose the correct simplification of the expression the quantity a to the 2nd power over b to the 3rd power all raised to the 4th power. a to the 6th power over b to the 7th power b12 a8b15 the quantity a to the 8th power over b to the 12th power

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  1. anonymous
    • one year ago
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    @jdoe0001

  2. anonymous
    • one year ago
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    is it d?\[\frac{ a^8 }{ b^12 }\]

  3. anonymous
    • one year ago
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    b^12, so like an exponent of 12, not 1...

  4. jdoe0001
    • one year ago
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    hmm what makes you think is d anyway?

  5. anonymous
    • one year ago
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    idk, I originally thought it was a, but idk

  6. jdoe0001
    • one year ago
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    \(\bf (a^n)^m\implies a^{n\cdot m}\quad thus \\ \quad \\ \left( \cfrac{a^2}{b^3} \right)^{\color{brown}{ 4}}\implies \left( \cfrac{a^{2\cdot {\color{brown}{ 4}}}}{b^{3\cdot {\color{brown}{ 4}}}} \right)\)

  7. jdoe0001
    • one year ago
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    so...should be obvous I'd think

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