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anonymous

  • one year ago

hi

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  1. anonymous
    • one year ago
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    what up

  2. anonymous
    • one year ago
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    wwwwwwwwwwwwwwwwoooooooooooooooooooooooooooooooooooooooooooowwwwwwwwwwwwwwwwwww

  3. anonymous
    • one year ago
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    this is a big one

  4. anonymous
    • one year ago
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    so what is your answer for part 1

  5. anonymous
    • one year ago
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    Create one trinomial function: f(x) = x^3 - 3x^2 - x + 3., and a linear function g(x) = (x - 1). Part 1. Divide f(x) by g(x). You must do it yourself using the long division you have learned f(x)/g(x) = (x^3 - 3x^2 + x + 3)/(x - 1) = x^2 - 2x + 3 (no remainder) Part 2: a = 1 -> f(a) = f(1) = 0 Part 3. Use the remainder theorem?

  6. anonymous
    • one year ago
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    do this help

  7. anonymous
    • one year ago
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    The Remainder Theorem starts with an unnamed polynomial p(x), where "p(x)" just means "some polynomial p whose variable is x". Then the Theorem talks about dividing that polynomial by some linear factor x – a, where a is just some number. Then, as a result of the long polynomial division, you end up with some polynomial answer q(x) (the "q" standing for "the quotient polynomial") and some polynomial remainder r(x). this is the defonition

  8. anonymous
    • one year ago
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    @plzzhelpme

  9. anonymous
    • one year ago
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    thanks

  10. anonymous
    • one year ago
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    @Napolions

  11. anonymous
    • one year ago
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    yes

  12. anonymous
    • one year ago
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    ok

  13. anonymous
    • one year ago
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    draw it out for me

  14. anonymous
    • one year ago
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    what would it mean

  15. anonymous
    • one year ago
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    and you are correct

  16. anonymous
    • one year ago
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    yes

  17. anonymous
    • one year ago
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    yes

  18. anonymous
    • one year ago
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    but do you want to under stand the equation

  19. anonymous
    • one year ago
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    |dw:1439425276723:dw|

  20. anonymous
    • one year ago
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    |dw:1439425459873:dw|

  21. anonymous
    • one year ago
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    WHAT UP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1 JK

  22. anonymous
    • one year ago
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    lol

  23. anonymous
    • one year ago
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    so what do you need

  24. anonymous
    • one year ago
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    u drew the same thing twice......

  25. anonymous
    • one year ago
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    @Napolions

  26. anonymous
    • one year ago
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    i know

  27. anonymous
    • one year ago
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    so how am i supposed to divide it???????? @Napolions

  28. anonymous
    • one year ago
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    the same way i shown u

  29. anonymous
    • one year ago
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    but u didnt show me anything.......... just forget it.......ill ask another question,,,,,,,, thx anyways..........

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spraguer (Moderator)
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