Two weather tracking stations are on the equator 146 miles apart. A weather balloon is located on a bearing of N 35°E from the western station and on a bearing of N 23°E from the eastern station. How far is the balloon from the western station?

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Two weather tracking stations are on the equator 146 miles apart. A weather balloon is located on a bearing of N 35°E from the western station and on a bearing of N 23°E from the eastern station. How far is the balloon from the western station?

Mathematics
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At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

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what mod is this?
6.01 precalc
|dw:1439476719101:dw| Use vectors to solve this problem. Find the end point of each line on the coordinate system, and then, add the two vectors.
wait how do I do that, sorry I really dont know how to do any of this so Im trying to catch up and this is a practice problem I have no idea how to do so can you show me step by step?
141miles...Distance between two points W and E = 146 miles and B is the position of B (balloon) Angle BWE =55 degrees and angle BEW =67 degrees therefore angle WBE = 180-55-67 =58 degrees Using sine formula w/sin (55)= b/sin(58) w= 146{sin 55/ sin 58) =141 miles
thanks!!
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wait so which one is it?

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