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anonymous

  • one year ago

Two weather tracking stations are on the equator 146 miles apart. A weather balloon is located on a bearing of N 35°E from the western station and on a bearing of N 23°E from the eastern station. How far is the balloon from the western station?

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  1. anonymous
    • one year ago
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    @peachpi

  2. anonymous
    • one year ago
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    @abb0t

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    • one year ago
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    @Nnesha

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    • one year ago
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    @aahmed123

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    • one year ago
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    @ParthKohli

  6. anonymous
    • one year ago
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    @sebaxtiangb

  7. sebaxtiangb
    • one year ago
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    what mod is this?

  8. anonymous
    • one year ago
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    6.01 precalc

  9. anonymous
    • one year ago
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    @iYuko

  10. Curry
    • one year ago
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    |dw:1439476719101:dw| Use vectors to solve this problem. Find the end point of each line on the coordinate system, and then, add the two vectors.

  11. anonymous
    • one year ago
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    wait how do I do that, sorry I really dont know how to do any of this so Im trying to catch up and this is a practice problem I have no idea how to do so can you show me step by step?

  12. anonymous
    • one year ago
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    @satellite73

  13. Falling_In_Katt
    • one year ago
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    141miles...Distance between two points W and E = 146 miles and B is the position of B (balloon) Angle BWE =55 degrees and angle BEW =67 degrees therefore angle WBE = 180-55-67 =58 degrees Using sine formula w/sin (55)= b/sin(58) w= 146{sin 55/ sin 58) =141 miles

  14. anonymous
    • one year ago
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    thanks!!

  15. NathalyN
    • one year ago
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  16. anonymous
    • one year ago
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    wait so which one is it?

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