anonymous
  • anonymous
hi
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
synthetic or long division?
anonymous
  • anonymous
|dw:1439426984814:dw|
anonymous
  • anonymous
what's \[\frac{ x^3 }{ x }\]

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
yes so put the x² up top and then multiply. What's \(x²(x-1)\)?|dw:1439427291282:dw|
anonymous
  • anonymous
now subtract. \[(x^3-3x^x+x+3)-(x^3-x^2)\]|dw:1439427418715:dw|
anonymous
  • anonymous
|dw:1439427556410:dw|
anonymous
  • anonymous
ok. now we just repeat the process. \[\frac{ -2x^2 }{ x }=x^2\]|dw:1439427710873:dw|
anonymous
  • anonymous
|dw:1439427762991:dw|
anonymous
  • anonymous
|dw:1439427804436:dw|
anonymous
  • anonymous
|dw:1439427828165:dw|
anonymous
  • anonymous
|dw:1439427860371:dw|
anonymous
  • anonymous
|dw:1439427685596:dw|
anonymous
  • anonymous
2 is the remainder, so the result is \[x^2-2x-2+\frac{ 2 }{ x-1 }\]
anonymous
  • anonymous
oh my god that is the exact question i had i can help you
anonymous
  • anonymous
peachip you are a gineus
anonymous
  • anonymous
complete that drawing also gives you the answer :)

Looking for something else?

Not the answer you are looking for? Search for more explanations.