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UnbelievableDreams
 one year ago
Confusing math question
UnbelievableDreams
 one year ago
Confusing math question

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mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1sin(x/2) = (sqrt (3))/2 Where is the sin theta equal to sqrt(3)/2 ?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439435025438:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1dw:1439435111856:dw

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1Keep in mind, all this is x/2, not x yet.

UnbelievableDreams
 one year ago
Best ResponseYou've already chosen the best response.1So it is {pi/3 + 4npi , 2pi/3 + 4npi} ?

mathstudent55
 one year ago
Best ResponseYou've already chosen the best response.1If \(\sin \theta = \dfrac{\sqrt 3}{2} \), then \(\theta = \dfrac{\pi}{3} + 2\pi n \) or \(\theta = \dfrac{2\pi}{3} + 2\pi n \) The equation had \(\sin \dfrac{x}{2} \), so now we let \(\theta = \dfrac{x}{2} \) and solve for x. If \(\theta = \dfrac{x}{2} = \dfrac{\pi}{3} + 2\pi n \) \(x = \dfrac{2\pi}{3} + 4\pi n\) or \(\dfrac{x}{2} = \dfrac{2\pi}{3} + 2\pi n\) \(x = \dfrac{4\pi}{3} + 4\pi n \)
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