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And\[x^\frac{ 1 }{ 3 } = \sqrt[3]{x}\]

I'm a bit confused with that second equation. How/when would I use that?

Put simply, you can simplify \(27^\frac{1}{3}\)

So does -4/3 get plugged into that or does 1/3

I already converted my equation

|dw:1439436483720:dw|

|dw:1439436579962:dw|

Let's use the negative exponent rule first.
|dw:1439436586340:dw|

|dw:1439436666466:dw|

I understand that so far but which exponent do I use? The already converted exponent?

Order of operations. Calculate what 27^(1/3) is and raise that number to the 4th power.

9^4?

Or 3^4

Yes. 3^4. The cube root of 27 is 3.

|dw:1439437072181:dw|

I was following the order of operations as I wrote it (with brackets).

So 81?

Well, don't forget, it's 1/81.

Ohhhhh okay. So what do I do with that?

|dw:1439437425872:dw|

Thank you so much everyone