Find the area of a regular hexagon with the given measurement.
6-inch radius
A = sq. in.

- anonymous

Find the area of a regular hexagon with the given measurement.
6-inch radius
A = sq. in.

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- jamiebookeater

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- anonymous

I have to put it into square root form.. how do I do that to the answer?

- anonymous

Oh, you have to do find the area using a square formula?

- anonymous

No, the question is as states, but it has to be put into a square root answer. I don't understand how to do it.. All the questions on this assignment are like this.

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## More answers

- anonymous

\[A=\frac{ 3\sqrt{3}r^2 }{ 2 }\]
Try it now.

- anonymous

|dw:1439445405018:dw| this is what I have to do for the answer. i will post the full question again.
Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.
Find the area of an equilateral triangle (regular 3-gon) with the given measurement.
6-inch radius
A = sq. in.

- anonymous

The boxes are where the numbers are supposed to go

- anonymous

Read my formula.

- anonymous

Do not simplify the square root.

- anonymous

So would this be my equation \[A= 3\sqrt{3}\left( 6 \right)^{2\frac{ }{ ? }}\]

- anonymous

all divided by 2?

- anonymous

yea

- anonymous

when i do this equation on my phone it comes out to 93.5307436097.. but it needs to be in the way I showed you. How do I make it into that way?

- abb0t

You can also divide it into triangles and figure out a formula tht way.A hexagon is: |dw:1439445847902:dw|

- abb0t

|dw:1439445867822:dw|

- anonymous

No do not simplify the square root!!!!!!!!!!!!!!!!

- anonymous

abb0t i showed that to him. He is more confused about it than just the regular area of hexagon

- abb0t

Area of a hexagon: \(\sf \large \color{red}{\frac{3\sqrt{3}}{2}a^2}\)

- anonymous

I know its (area of equilateral triangle x 6

- abb0t

a = the value of a side.

- anonymous

My phone did it myself, and actually im not a guy.. Im a senior girl. I know Im not good at this, Im better at algebra. so basically @Shalante my answer is right that is just reduced?

- abb0t

therefore, \(\sf \large \color{blue}{\frac{3\sqrt{3}}{2}6^2}\)

- anonymous

hey chevy253, stop using your calculator to solve it, since the answer does not requires it.
Understand????

- anonymous

Oopsie :)

- anonymous

Yea, just reduce the fraction, but leave the square root alone.

- anonymous

I dont know how to do it without a calculator.. and all my calculator keeps doing is reducing it.

- abb0t

memorize the first 4 square roots, 0-4
it will help a lot during exam time.
\(\sf \sqrt{2} \approx 1.4\)
\(\sf \sqrt{3} \approx 1.7\)
\(\sf \sqrt{4} = 2\)

- anonymous

Do you know why your answer requires a square root? because it has a square root as you can see.
Now put that square number in your answer. And to the other fraction

- anonymous

For the other fraction just solve it and put it there.

- anonymous

but if i put this \[3\sqrt{3}\] i have to have another number in front of it. if you look at the picture there are two numbers before the square root and only one after

- anonymous

Look at your formula and answer carefully and see how it will fit together.

- anonymous

you did the math wrong madame.

- anonymous

look at the formula again.

- abb0t

O.M.G.

- anonymous

alright so if i leave the sqaure root alone i come up with this \[3\sqrt{3 \left( 36 \right)}\] over 2.. is that right so far?

- anonymous

the 36 is out of the square root.

- anonymous

so if its out then 36/2 is 18.. but then how would i plug that into the way the answer is supposed to be?

- anonymous

would I multiply it...?

- anonymous

you forgot to multiply the 36 by 3, then you divide it by 2

- anonymous

oh so I leave the 3 in front of the sqare root alone, but use the one behind it? so it would be 54.. but that still wont work.. I feel like im still doing it wrong. I came up with this \[A= 3\sqrt{54}\]

- anonymous

Here, just look.
Nice job for trying.
\[\frac{ 3\sqrt{3} }{ 2 } r^2\]
r=6in
Plug in r with 6
\[\frac{ 3\sqrt{3} }{ 2 }(36)\]
\[\frac{ (36)(3)\sqrt{3} }{ 2 }\]
\[\frac{ 108\sqrt{3} }{ 2 }\]
\[=54\sqrt{3}\]

- anonymous

That is the formula for area of a hexagon.

- anonymous

Oh shoot... alright im ganna see if I can do a different one on my own, will you see if Im right?

- anonymous

Sure.

- anonymous

This is the question Im ganna work it out real quick Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers.
Find the area of a regular hexagon with the given measurement.
apothem
A =

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