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anonymous

  • one year ago

Find the area of a regular hexagon with the given measurement. 6-inch radius A = sq. in.

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  1. anonymous
    • one year ago
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    I have to put it into square root form.. how do I do that to the answer?

  2. anonymous
    • one year ago
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    Oh, you have to do find the area using a square formula?

  3. anonymous
    • one year ago
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    No, the question is as states, but it has to be put into a square root answer. I don't understand how to do it.. All the questions on this assignment are like this.

  4. anonymous
    • one year ago
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    \[A=\frac{ 3\sqrt{3}r^2 }{ 2 }\] Try it now.

  5. anonymous
    • one year ago
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    |dw:1439445405018:dw| this is what I have to do for the answer. i will post the full question again. Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers. Find the area of an equilateral triangle (regular 3-gon) with the given measurement. 6-inch radius A = sq. in.

  6. anonymous
    • one year ago
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    The boxes are where the numbers are supposed to go

  7. anonymous
    • one year ago
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    Read my formula.

  8. anonymous
    • one year ago
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    Do not simplify the square root.

  9. anonymous
    • one year ago
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    So would this be my equation \[A= 3\sqrt{3}\left( 6 \right)^{2\frac{ }{ ? }}\]

  10. anonymous
    • one year ago
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    all divided by 2?

  11. anonymous
    • one year ago
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    yea

  12. anonymous
    • one year ago
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    when i do this equation on my phone it comes out to 93.5307436097.. but it needs to be in the way I showed you. How do I make it into that way?

  13. abb0t
    • one year ago
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    You can also divide it into triangles and figure out a formula tht way.A hexagon is: |dw:1439445847902:dw|

  14. abb0t
    • one year ago
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    |dw:1439445867822:dw|

  15. anonymous
    • one year ago
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    No do not simplify the square root!!!!!!!!!!!!!!!!

  16. anonymous
    • one year ago
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    abb0t i showed that to him. He is more confused about it than just the regular area of hexagon

  17. abb0t
    • one year ago
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    Area of a hexagon: \(\sf \large \color{red}{\frac{3\sqrt{3}}{2}a^2}\)

  18. anonymous
    • one year ago
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    I know its (area of equilateral triangle x 6

  19. abb0t
    • one year ago
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    a = the value of a side.

  20. anonymous
    • one year ago
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    My phone did it myself, and actually im not a guy.. Im a senior girl. I know Im not good at this, Im better at algebra. so basically @Shalante my answer is right that is just reduced?

  21. abb0t
    • one year ago
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    therefore, \(\sf \large \color{blue}{\frac{3\sqrt{3}}{2}6^2}\)

  22. anonymous
    • one year ago
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    hey chevy253, stop using your calculator to solve it, since the answer does not requires it. Understand????

  23. anonymous
    • one year ago
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    Oopsie :)

  24. anonymous
    • one year ago
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    Yea, just reduce the fraction, but leave the square root alone.

  25. anonymous
    • one year ago
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    I dont know how to do it without a calculator.. and all my calculator keeps doing is reducing it.

  26. abb0t
    • one year ago
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    memorize the first 4 square roots, 0-4 it will help a lot during exam time. \(\sf \sqrt{2} \approx 1.4\) \(\sf \sqrt{3} \approx 1.7\) \(\sf \sqrt{4} = 2\)

  27. anonymous
    • one year ago
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    Do you know why your answer requires a square root? because it has a square root as you can see. Now put that square number in your answer. And to the other fraction

  28. anonymous
    • one year ago
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    For the other fraction just solve it and put it there.

  29. anonymous
    • one year ago
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    but if i put this \[3\sqrt{3}\] i have to have another number in front of it. if you look at the picture there are two numbers before the square root and only one after

  30. anonymous
    • one year ago
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    Look at your formula and answer carefully and see how it will fit together.

  31. anonymous
    • one year ago
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    you did the math wrong madame.

  32. anonymous
    • one year ago
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    look at the formula again.

  33. abb0t
    • one year ago
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    O.M.G.

  34. anonymous
    • one year ago
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    alright so if i leave the sqaure root alone i come up with this \[3\sqrt{3 \left( 36 \right)}\] over 2.. is that right so far?

  35. anonymous
    • one year ago
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    the 36 is out of the square root.

  36. anonymous
    • one year ago
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    so if its out then 36/2 is 18.. but then how would i plug that into the way the answer is supposed to be?

  37. anonymous
    • one year ago
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    would I multiply it...?

  38. anonymous
    • one year ago
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    you forgot to multiply the 36 by 3, then you divide it by 2

  39. anonymous
    • one year ago
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    oh so I leave the 3 in front of the sqare root alone, but use the one behind it? so it would be 54.. but that still wont work.. I feel like im still doing it wrong. I came up with this \[A= 3\sqrt{54}\]

  40. anonymous
    • one year ago
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    Here, just look. Nice job for trying. \[\frac{ 3\sqrt{3} }{ 2 } r^2\] r=6in Plug in r with 6 \[\frac{ 3\sqrt{3} }{ 2 }(36)\] \[\frac{ (36)(3)\sqrt{3} }{ 2 }\] \[\frac{ 108\sqrt{3} }{ 2 }\] \[=54\sqrt{3}\]

  41. anonymous
    • one year ago
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    That is the formula for area of a hexagon.

  42. anonymous
    • one year ago
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    Oh shoot... alright im ganna see if I can do a different one on my own, will you see if Im right?

  43. anonymous
    • one year ago
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    Sure.

  44. anonymous
    • one year ago
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    This is the question Im ganna work it out real quick Click an item in the list or group of pictures at the bottom of the problem and, holding the button down, drag it into the correct position in the answer box. Release your mouse button when the item is place. If you change your mind, drag the item to the trashcan. Click the trashcan to clear all your answers. Find the area of a regular hexagon with the given measurement. apothem A =

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