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i have already done this
yeah, I don't understand how they want the statistics either for the 2, or 2 each, of cats and dogs on the chart
so what were ur answers for: HH - HT - TH - and TT? -
hh=11 ht=17 th=8 tt=14
ok... so from ur screenshot: which question do u want to go through first?
the first one and work from there
k_ so cats are Heads, and Dogs are Tails according to the start of ur Q: having cat or dog is 50:50 "theoretical" probability so: Q1 - theoretical Probability of 2 cats OR 2 dogs = P(HH) OR P(TT) = P(HH) + P(TT) Theoretical probability of HH =0.25 Theoretical probability of TH =0.25 Theoretical probability of HT =0.25 Theoretical probability of TT =0.25 so solve = P(HH) + P(TT) @bubbleslove1234 ?
do you know what i should get cause i am soooooooooooo confused
oww my brain hurts
Theoretical probability is: P(HH) =0.25 (or 25%) P(TH) =0.25 (or 25%) P(HT) =0.25 (or 25%) P(TT) =0.25 (or 25%) so Q1. solve = P(HH) + P(TT)
okay so 25% times 50
no, sorry u can either use percentages or use decimals, but u can't use both at the same time, sorry P(HH) = 0.25 P(TT) = 0.25 so = P(HH) + P(TT) =?
did you get the Question 1 answer? dog and cat?
nope not yet but i need fast help cause it is due today
no, for question 1, we only care about Theoretical results... not actual one we get from flipping a coin so Theoretical probability of 2 heads is 25% of the time... so P(HH) = 0.25 and the Theoretical probability of 2 tails is 25% of the time... so P(TT) = 0.25 so whats .25 + .25 ?
perfect. PHH + PTT = 0.50 .... or 50 % so Q1 = 50% chance
oh so is that the answer
Q1. chance family has 2 cats or 2 dogs? = P(CC) or P(DD) = 0.5 .... or 50% yep, answer
for the first one
Q2. how does 2 coins simulate which 2 pets a family has? answer: 50% chance of choosing a cat or a dog, and they chose twice (50% either cat or dog, then 50% chance either cat or dog for the 2nd pet also) so exactly as flipping a coin... twice (50% either heads or tail, then 50% chance either head or tail on the 2nd toss also)
Q3.check if this is correct: ur results were: |dw:1439454960600:dw|
perfect now, calculate your results for P(HH) and P(TT) P(HH) = number of results that were HH / total number of flips =11/50 = what? (in decimals) P(TT) = number of results that were *TT / total number of flips =14/50 = what? (in decimals) @bubbleslove1234 ?
P(HH) = 0.22 P(TT) =0.28
absolutely right so: Experimental Probability of 2 cats or 2 dogs = same probability as flipping a coin 50 times and getting 2 heads or 2 tails so = P(HH) + P(TT) = 0.22 + 0.28 = ???
okay for question 1, Dog/Cat 1 1 2 0 0 2 now, in the question its given 2 cats or 2 dogs, so trials are 3, so, its 2/3
For question 2, just assign head as dog and tail as cat
now, hh=11 ht=17 th=8 tt=14 if this your data..... then count head head+tail+tail (according to question4 2 dogs and 2 cats) so, 11+14=25 now for probability divide by the frequency, so answer is 25/50
can we move to Q5
for question 5, C=Cat, D=Dog CCD CDD DDD DCC DDC CCC CDC DCD now, count where CCC and DDD is there which is 2. 2/8 , where 8 is the frequesncy. 2/8 is the probability
hey, back and working, but keep going, happy to watch Q5: perfect, but 1 question: how did u get 2/8 for Q5... but only 2/3 for Q1? should it not be 2/4...?
Q5 and Q1 has no relation (very important)
no. categorically: no. Q1 and Q5 are totally related ;)
Q5 is correct.....
but Q1 I missed something.......
np dude ;)
Now question 6
H=Head, T=Tail In the table given in Question, replace that with TTH THH HHH HTT HHT TTT THT HTH
he means : flip a coin 3 times, and record the results current simulation is; flip a coin 2 times
so what is the answer
only 3 times
flip a coin... 3 times.... record the results... repeat 50 times or flip 3 coins at the same time... 50 times