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anonymous
 one year ago
OMG!!!!!!!!!!! HELP PLZZZZZZZZ
anonymous
 one year ago
OMG!!!!!!!!!!! HELP PLZZZZZZZZ

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Jack1
 one year ago
Best ResponseYou've already chosen the best response.1for this... u srsly need to flip a coin 50 times and fill in the table from ur results @bubbleslove1234 ... sorry, till u do we cant help u hey

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i have already done this

LunyMoony
 one year ago
Best ResponseYou've already chosen the best response.0yeah, I don't understand how they want the statistics either for the 2, or 2 each, of cats and dogs on the chart

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1so what were ur answers for: HH  HT  TH  and TT? 

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0hh=11 ht=17 th=8 tt=14

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1ok... so from ur screenshot: which question do u want to go through first?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0the first one and work from there

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1k_ so cats are Heads, and Dogs are Tails according to the start of ur Q: having cat or dog is 50:50 "theoretical" probability so: Q1  theoretical Probability of 2 cats OR 2 dogs = P(HH) OR P(TT) = P(HH) + P(TT) Theoretical probability of HH =0.25 Theoretical probability of TH =0.25 Theoretical probability of HT =0.25 Theoretical probability of TT =0.25 so solve = P(HH) + P(TT) @bubbleslove1234 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0do you know what i should get cause i am soooooooooooo confused

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1Theoretical probability is: P(HH) =0.25 (or 25%) P(TH) =0.25 (or 25%) P(HT) =0.25 (or 25%) P(TT) =0.25 (or 25%) so Q1. solve = P(HH) + P(TT)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0okay so 25% times 50

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1no, sorry u can either use percentages or use decimals, but u can't use both at the same time, sorry P(HH) = 0.25 P(TT) = 0.25 so = P(HH) + P(TT) =?

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1P(HH) = 0.25 P(TT) = 0.25 so P(HH) + P(TT) = ????? @bubbleslove1234 ...?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0p(11)=0.25 p(14)=0.25

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1did you get the Question 1 answer? dog and cat?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0nope not yet but i need fast help cause it is due today

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1no, for question 1, we only care about Theoretical results... not actual one we get from flipping a coin so Theoretical probability of 2 heads is 25% of the time... so P(HH) = 0.25 and the Theoretical probability of 2 tails is 25% of the time... so P(TT) = 0.25 so whats .25 + .25 ?

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1perfect. PHH + PTT = 0.50 .... or 50 % so Q1 = 50% chance

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0oh so is that the answer

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1Q1. chance family has 2 cats or 2 dogs? = P(CC) or P(DD) = 0.5 .... or 50% yep, answer

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1Q2. how does 2 coins simulate which 2 pets a family has? answer: 50% chance of choosing a cat or a dog, and they chose twice (50% either cat or dog, then 50% chance either cat or dog for the 2nd pet also) so exactly as flipping a coin... twice (50% either heads or tail, then 50% chance either head or tail on the 2nd toss also)

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1Q3.check if this is correct: ur results were: dw:1439454960600:dw

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1Q4. Experimental Probability In ur test, how many times did u flip the coin? @bubbleslove1234 ?

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1perfect now, calculate your results for P(HH) and P(TT) P(HH) = number of results that were HH / total number of flips =11/50 = what? (in decimals) P(TT) = number of results that were *TT / total number of flips =14/50 = what? (in decimals) @bubbleslove1234 ?

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0P(HH) = 0.22 P(TT) =0.28

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1absolutely right so: Experimental Probability of 2 cats or 2 dogs = same probability as flipping a coin 50 times and getting 2 heads or 2 tails so = P(HH) + P(TT) = 0.22 + 0.28 = ???

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1@bubbleslove1234 should I try?

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1okay for question 1, Dog/Cat 1 1 2 0 0 2 now, in the question its given 2 cats or 2 dogs, so trials are 3, so, its 2/3

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1sorry my page froze... and is being glitchy can u finish @arindameducationusc please?

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1okay @Jack1 let me try.........

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1For question 2, just assign head as dog and tail as cat

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1now, hh=11 ht=17 th=8 tt=14 if this your data..... then count head head+tail+tail (according to question4 2 dogs and 2 cats) so, 11+14=25 now for probability divide by the frequency, so answer is 25/50

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1for question 5, C=Cat, D=Dog CCD CDD DDD DCC DDC CCC CDC DCD now, count where CCC and DDD is there which is 2. 2/8 , where 8 is the frequesncy. 2/8 is the probability

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1hey, back and working, but keep going, happy to watch Q5: perfect, but 1 question: how did u get 2/8 for Q5... but only 2/3 for Q1? should it not be 2/4...?

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1Q5 and Q1 has no relation (very important)

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1one sec....

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1no. categorically: no. Q1 and Q5 are totally related ;)

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1Q5 is correct.....

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1but Q1 I missed something.......

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1if D=Dog C=Cat CC DD CD DC so yes it is 2/4. Thank you @Jack1

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1Now question 6

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1H=Head, T=Tail In the table given in Question, replace that with TTH THH HHH HTT HHT TTT THT HTH

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1he means : flip a coin 3 times, and record the results current simulation is; flip a coin 2 times

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0so what is the answer

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1@Jack1 Exactly ! Flipping coins 3 times.... and record observations

Jack1
 one year ago
Best ResponseYou've already chosen the best response.1flip a coin... 3 times.... record the results... repeat 50 times or flip 3 coins at the same time... 50 times

arindameducationusc
 one year ago
Best ResponseYou've already chosen the best response.1Good job @bubbleslove1234 ... Was my attempt useful @bubbleslove1234 ?
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