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anonymous
 one year ago
A water tank 3m in diameter and 6m high is made from a steel taving a thickness of 12mm. When tank is filled w/water determine the circumference stress.
Det. the tank stressL at the buttom of the tank when it is filled w/water.
if the circumference stress is limited to 5Mpa what is the max. height of the water?
anonymous
 one year ago
A water tank 3m in diameter and 6m high is made from a steel taving a thickness of 12mm. When tank is filled w/water determine the circumference stress. Det. the tank stressL at the buttom of the tank when it is filled w/water. if the circumference stress is limited to 5Mpa what is the max. height of the water?

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Jack1
 one year ago
Best ResponseYou've already chosen the best response.0Volume of tank = ? @patbigFat

Jack1
 one year ago
Best ResponseYou've already chosen the best response.0nono... can u work it out please?

Jack1
 one year ago
Best ResponseYou've already chosen the best response.0yeah... what number are u plugging into ur equation tho... for r?

Jack1
 one year ago
Best ResponseYou've already chosen the best response.0no... 3 = diameter radius is half of diameter

Jack1
 one year ago
Best ResponseYou've already chosen the best response.0so give it another shot with r = 1.5 so V=??

Jack1
 one year ago
Best ResponseYou've already chosen the best response.0i got 42.41... how are u calculating this? 3.14159 x 1.5^2 x 6 =42.4115

Jack1
 one year ago
Best ResponseYou've already chosen the best response.0all good dude now... surface area of inside of tank? = ??

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0i tot when i sqr 1.5 = 3 so i did a manual calculating .... my bad....

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0SA = 2 × pi × r2 + 2 × pi × r × h ?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0hoop stress \(\large \sigma_{\theta} = \frac{P \ D}{2t}\) D = 3, t = 12mm get pressure from bernoulli \(P = \rho g h\) h = 6 plug and play [if you know some calculus, the formula is deriveable; but i think it is also pretty standard for thin walled pressure vessels. been ages since i did this stuff.] you can get steel's material properties online, for the end bit you will need its tensile strength and the hoop stress is measured around the circumference , ie tangentially to the circle

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0actually you don't need to look at steel at all you are told "the circumference stress is limited to 5Mpa" so you are now solving h for a given \(\sigma_{\theta}\)

anonymous
 one year ago
Best ResponseYou've already chosen the best response.0Uhmm.m P=pgh by the way what's "pg" ?

IrishBoy123
 one year ago
Best ResponseYou've already chosen the best response.0\(\rho \equiv\) density of fluid, here water g \(\equiv\) gravity = \(9.8 m/s^2\)

Jack1
 one year ago
Best ResponseYou've already chosen the best response.0sorry guys, fell asleep last night
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